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NISA [10]
3 years ago
10

The two figures above are regular. If s and t represent the lengths of the segments indicated in the figures, which statement is

true?
A. s > t

B. t > s

C. s = t

D. No comparison can be made.

Mathematics
1 answer:
adoni [48]3 years ago
6 0
The answer:  s is greater than t ,, choice A

Explanation:

Each interior angle of a regular octagon = 135 degrees
Each interior angle of a regular hexagon = 120 degrees

Thus, ∠PBA = 67.5 degrees and ∠QNM = 60 degrees
In the octagon name the intersecting point of the altitude and the side; 'x'
In the hexagon name the intersecting point of the altitude and the side; 'y'
Consider the right triangles PBX and QNY
Now we can argue that the side opposite of the larger angle is going to be larger in those respective right triangles.
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Find the area of the polygon defined by the coordinates (0,-5),(-5,0),(-15,-20),and(-20,-15)
alekssr [168]

Area of the polygon defined by the given points is 62.5 sq units

Step-by-step explanation:

Step 1 :    

Let P be the point (-5,0)  Q = (0,-5), R = (-15,-20) and S = (20,-15)

We have to to find the area of the polygon PQRS

Step 2 :

The area of polygon given the vertices (x(x_{1} ,y_{1} ), (x_{2} ,y_{2})  ... (x_{n} ,y_{n} ) is given by

Area  = mod ( (x_{1} y_{2}  - y_{1}x_{2}) + (x_{2} y_{3}  - y_{2}x_{3}) + ... (x_{n} y_{1}  - y_{n}x_{1}) ) ÷ 2

Where  x_{n} is the vertex n's x coordinate , y_{n} is the vertex n's y coordinate

Substituting the corresponding values ,

Area of PQRS = mod ( (25 - 0)+ (0-75) +(300-300) +( 0-75)  ) ÷ 2

                       = mod (25-75+0-75) ÷ 2

                       = mod (-125) ÷ 2 = 125 ÷ 2 = 62.5 sq units

Step 3 :    

Answer :

Area of the polygon defined by the given points is 62.5 sq units

4 0
3 years ago
Pls help with asap thxxu! :)
Stella [2.4K]

Answer:

C- Equilateral triangle

Step-by-step explanation:

I am not very sure dear

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