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NISA [10]
3 years ago
10

The two figures above are regular. If s and t represent the lengths of the segments indicated in the figures, which statement is

true?
A. s > t

B. t > s

C. s = t

D. No comparison can be made.

Mathematics
1 answer:
adoni [48]3 years ago
6 0
The answer:  s is greater than t ,, choice A

Explanation:

Each interior angle of a regular octagon = 135 degrees
Each interior angle of a regular hexagon = 120 degrees

Thus, ∠PBA = 67.5 degrees and ∠QNM = 60 degrees
In the octagon name the intersecting point of the altitude and the side; 'x'
In the hexagon name the intersecting point of the altitude and the side; 'y'
Consider the right triangles PBX and QNY
Now we can argue that the side opposite of the larger angle is going to be larger in those respective right triangles.
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In a trapezoid the lengths of bases are 11 and 18. The lengths of legs are 3 and 7. The extensions of the legs meet at some poin
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Answer:  7\frac{5}{7} unit and 18 unit

Step-by-step explanation:

Let ABCD is a trapezoid where AB and CD are the bases. ( In which AB is greatest base which shown in below figure)

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Now, we have ( According to the question ),

AB = 18 unit, BC = 7 unit, AD = 3 unit and DC = 11 unit.

Here the leg AD extends from point D.

Similarly leg BC extends from point C.

Let they meet at point P ( shown in below diagram)

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∠PDC ≅ ∠PAB ( because DC ║ AB )

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∠DPC ≅ ∠ APB ( reflexive)

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\triangle PDC \sim \triangle PAB

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And, PB = PC + CB = 11 + 7 = 18


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