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Debora [2.8K]
3 years ago
14

Which could be the dimensions of a rectangular prism whose surface area is greater than 140 square feet? Select three options. 0

6 feet by 2 feet by 3 feet 6 feet by 5 feet by 4 feet 7 feet by 6 feet by 4 feet 8 feet by 3 feet by 7 feet 8 feet by 4 feet by 3 feet​
Mathematics
2 answers:
CaHeK987 [17]3 years ago
5 0

Answer:

bcd

Step-by-step explanation:

olya-2409 [2.1K]3 years ago
4 0

Answer:

I think the answers are...

B. 6 feet by 5 feet by 4 feet

C. 7 feet by 6 feet by 4 feet

D.  8 feet by 3 feet by 7 feet

(I'm so sorry if it's wrong)

Hope this Helps!

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Solve the formula for the indicated variable. EASY 40 POINTS!!!!!!!!!!!!!!!!
vlada-n [284]

Answer:

d = Nc + x

Step-by-step explanation:

Given

N = \frac{d-x}{c}

Multiply both sides by c to clear the fraction

Nc = d - x ( add x to both sides )

Nc + x = d

8 0
3 years ago
Mathematics textbook grade 4
n200080 [17]

Answer:

so what are u trying to say ,,!!!

Step-by-step explanation:

HAVE A NICE DAY

3 0
3 years ago
Read 2 more answers
Given: KLMN is a trapezoid m∠N = m∠KML ME ⊥ KN , ME = 3√5 , KE = 8, LM:KN = 3:5 Find: KM, LM, KN, Area of KLMN
lora16 [44]
Q1)Find KM
As ME is perpendicular to KN, ∠KEM is a right angle
Therefore ΔKEM is a right angled triangle 
KE is given and and ME is also given, we need to find KM
for this we can use Pythogoras' theorem where the square of hypotenuse is equal to the sum of the squares of the adjacent sides.
KM² = KE² + ME²
KM² = 8² + (3√5)²
       = 64 + 9x5
KM = √109
KM = 10.44

Q2)Find LM
It is said that ratio of LM:KN is 3:5
Therefore if we take the length of one unit as x
length of LM is 3x
and the length of KN is 5x
KN is greater than LM by 2 units 
If we take the figure ∠K and ∠N are equal. 
Since the angles on opposite sides of the bases are equal then this is called an isosceles trapezoid. So if we draw a line from L that cuts KN perpendicularly at D, ΔKEM and ΔLDN are congruent therefore KE = DN
since KN is greater than LM due to KE and DN , the extra 2 units of KN correspond to 16 units 
KN = LM + 2x 
2x = KE + DN
2x = 8+8
x = 8
LM = 3x = 3*8 = 24

Q3)Find KN 
Since ∠K and ∠N are equal, when we take the 2 triangles KEM and LDN, they both have;
same height ME = LD perpendicular distance between the 2 parallel sides 
same right angle when the perpendicular lines cut KN
∠K = ∠N 
when 2 angles and one side of one triangle is equal to two angles and one side on another triangle then the 2 triangles are congruent according to AAS theorem (AAS). Therefore KE = DN 
the distance ED = LM
Therefore KN = KE + ED + DN
 since ED = LM = 24
and KE + DN = 16
KN = 16 + 24 = 40
another way is since KN = 5x and x = 8
KN = 5 * 8 = 40

Q4)Find area KLMN
Area of trapezium can be calculated using the following general equation 
Area = 1/2 x perpendicular height between parallel lines x (sum of the parallel sides)
where perpendicular height - ME
2 parallel sides are KN and LM
substituting values into the general equation
Area = 1/2 * ME * (KN+ LM) 
         = 1/2 * 3√5 * (40 + 24)
         = 1/2 * 3√5 * 64
         = 3 x 2.23 * 32
         = 214.66 units²


8 0
3 years ago
Read 2 more answers
5z3 - 224 - 9z2 + 2<br> What is the degree of the polynomial?<br> I
hoa [83]

Answer:

5{z}^{3}-222-9{z}^{2}5z

​3

​​ −222−9z

​2

Step-by-step explanation:

1 Collect like terms.

5{z}^{3}+(-224+2)-9{z}^{2}5z

​3

​​ +(−224+2)−9z

​2

​​  

2 Simplify.

5{z}^{3}-222-9{z}^{2}5z

​3

​​ −222−9z

​2

​​  

Done

7 0
3 years ago
Pls help I’m failing
jeka94

The equation <u>6 + 9a = 51</u> can help find out how many adults were in the group.

4 0
3 years ago
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