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Grace [21]
2 years ago
8

The expression below represents the perimeter of a square in centimeters.

Mathematics
1 answer:
Aleks [24]2 years ago
8 0

Answer:

34

Step-by-step explanation:

4(8.5) = 34

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The cowboy rode into town on friday stayed there for 3 days and left on friday how can that be
fgiga [73]
His horse's name is Friday.
6 0
4 years ago
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Digital Lesson
kifflom [539]

Answer:

about 28

Step-by-step explanation:

7 0
3 years ago
The net of a rectangular prism is shown below.
Mamont248 [21]

Answer:

28

Step-by-step explanation:

Using a net to find the surface area of a rectangular prism

Finding the areas of each of the rectangles and squares of the net of a rectangular prism and adding up those areas gives the surface area or total surface area of the prism.

For example, if the length of one side of the cube 4 units then the area of one its face is 4 × 4 = 16 square units. From the net, we can see that there are six equal faces and so we get the total surface area is 6 × 16 = 96 square units.

Surface Area of a Rectangular Prism using Nets

A rectangular prism or cuboid is formed by folding a net as shown −

Cuboid

We can see from the net that there are two rectangles with dimensions 3 cm by 6 cm, two rectangles with dimensions 2 cm by 6 cm and two rectangles with dimensions 2 cm by 3 cm. The total surface area is then

2 × 3 × 6 + 2 × 2 × 6 + 2 × 2 × 3 = 72 cm2

Example 1:

Find the surface area of the given rectangular prism in square cm.

Rectangular Prism in Square cm

Solution

Step 1:

Using net, the surface area of a rectangular prism

= 2lw+wh+lh; l = 6 ; w = 5; h = 3

Step 2:

Surface area of given prism = 26×5+6×3+3×5

= 230+18+15

= 126 square cm

Example 2:

Find the surface area of the given rectangular prism in square cm.

Rectangular Prism Square cm

Solution

Step 1:

Using net, the surface area of a rectangular prism

= 2lw+wh+lh; l = 5; w = 6; h = 4

Step 2:

Surface area of given prism = 25×6+5×4+6×4

= 230+20+24

= 148 square cm

6 0
3 years ago
Read 2 more answers
In △ABC acute angles are in the ratio 5:1, i.e. ∠BAC:∠ABC = 5:1. If CH is an altitude and CL is an angle bisector, find m∠HCL.
tekilochka [14]

If m\angle BAC:m\angle ABC=5:1, then m\angla BAC=(5x)^{\circ},\ m\angle ABC=x^{\circ}.

The sum of the measures of the interior angles of the triangle is always 180°, then

m\angle ACB=180^{\circ}-x^{\circ}-(5x)^{\circ}=180^{\circ}-(6x)^{\circ}.

Since CL is bisector, then

m\angle BCL=m\angle ACL=\dfrac{180^{\circ}-(6x)^{\circ}}{2}=90^{\circ}-(3x)^{\circ}.

Consider right triangle ACH. In this triangle

m\angle ACH=180^{\circ}-90^{\circ}-(5x)^{\circ}=90^{\circ}-(5x)^{\circ}.

Now angle HCL has measure

m\angle HCL=m\angle ACL-m\angle ACH=90^{\circ}-(3x)^{\circ}-(90^{\circ}-(5x)^{\circ})=(2x)^{\circ}=2m\angle ABC.

Answer: m\angle HCL=2m\angle ABC.

6 0
4 years ago
Solve for x. round to the nearest tenth
konstantin123 [22]

Answer:

x ≈ 11.1

Step-by-step explanation:

Using the cosine ratio in the right triangle.

cos42° = \frac{adjacent}{hypotenuse} = \frac{x}{15} ( multiply both sides by 15 )

15 × cos42° = x, then

x ≈ 11.1 ( to the nearest tenth )

3 0
3 years ago
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