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Snowcat [4.5K]
3 years ago
5

What is the difference in height between an albatross flying at 100 m above the surface of the ocean and a shark swimming 30 m b

elow the surface?
Mathematics
1 answer:
Lelechka [254]3 years ago
6 0

Answer:  130 meters

Step-by-step explanation:

We have to let the "surface of the ocean" be at 0 height.

So,

anything above surface has POSITIVE height

and anything below surface has NEGATIVE height

The albatross is 100 m above, so we can say its height is:

+100 meters

The shark is 30 m below, so we can say its height is:

-30 meters

The difference in height is thus:

100 - (-30) = 100 + 30 = 130 meters

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A tank with a capacity of 500 gal originally contains 200 gal of water with 100 lb of salt in solution. Water containing 1 lb of
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Let A(t) denote the amount of salt in the tank at time t.

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(in case you're unsure about the denominator: the tank starts off with 200 gal of solution, and each minute solution flows in at a rate of 3 gal/min and thus the tank gains (3 gal/min) * (1 min) = 3 gal. At the same time, solution flows out at a rate of 2 gal/min and thus the tank loses 2 gal, giving a net change in volume of (3 - 2)*t = t gal)

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\dfrac{\mathrm dA(t)}{\mathrm dt}-\dfrac{2A(t)}{200+t}=3

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(200+t)^{-1}\dfrac{\mathrm dA(t)}{\mathrm dt}-2(200+t)^{-3}A()=3(200+t)^{-2}

\implies\dfrac{\mathrm d}{\mathrm dt}\bigg((200+t)^{-2}A(t)\bigg)=3(200+t)^{-2}

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Theoretically, the amount of salt in the tank will increase forever, since A(t)\to\infty as t\to\infty.

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