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Rus_ich [418]
3 years ago
14

6/8 = 30/___ what is the denominator for the 30 part

Mathematics
2 answers:
astra-53 [7]3 years ago
6 0
6/8 = 30/40

Hope this helped!
Aliun [14]3 years ago
6 0
 try mutipliying 8 times 5 that will give you your answer because 6 times 5 gave you the numerater so try the denominator
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How much percent of 200 miles is in 150 miles
satela [25.4K]
❅ 300%
You can do this by multiplying
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4 0
3 years ago
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What is the answer to this.....<br> 56kg X 3/8
Nina [5.8K]

Answer:

21 Kg

Step-by-step explanation:

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2 years ago
A line has a slope of 1/2 between the points (10,5) and (16,n). What is the value of n?
Nataly_w [17]
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5 0
3 years ago
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Helen [10]

- 10b

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3 0
3 years ago
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What is the first derivative of r with respect to t (i.e., differentiate r with respect to t)? r = 5/(t2)Note: Use ^ to show exp
adelina 88 [10]

Answer:

The first derivative of r(t) = 5\cdot t^{-2} (r(t)=5*t^{-2}) with respect to t is r'(t) = -10\cdot t^{-3} (r'(t) = -10*t^{-3}).

Step-by-step explanation:

Let be r(t) = \frac{5}{t^{2}}, which can be rewritten as r(t) = 5\cdot t^{-2}. The rule of differentiation for a potential function multiplied by a constant is:

\frac{d}{dt}(c \cdot t^{n}) = n\cdot c \cdot t^{n-1}, \forall \,n\neq 0

Then,

r'(t) = (-2)\cdot 5\cdot t^{-3}

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The first derivative of r(t) = 5\cdot t^{-2} (r(t)=5*t^{-2}) with respect to t is r'(t) = -10\cdot t^{-3} (r'(t) = -10*t^{-3}).

5 0
3 years ago
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