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rewona [7]
2 years ago
6

Question 1

Mathematics
1 answer:
Aleksandr-060686 [28]2 years ago
7 0

Answer:

<em>T5 = 512</em>

Step-by-step explanation:

Given the sequence

2,8, 32, 128,...

The sequence is a geometric progression

nth term of a geometric progression is expressed as:

Tn = ar^n-1

a is the first term = 2

n is the number of terms = 5 (next term is the 5th term)

r is the common ratio = 8/2 = 32/8 = 4

Substitute and get the fifth term

T5 = 2(4)^5-1

T5 = 2(4)^4

T5 = 2*256

<em>T5 = 512</em>

<em>Hence the next term is 512</em>

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I have 8 pennies and some quarters, nickels, and dimes. The number of pennies plus nickels equals the number of dimes. I have 3
Darina [25.2K]

There are five nickels.

Let <em>w</em> = the number of pennies; <em>x</em> = the number of nickels; <em>y</em> = the number of dimes; <em>z </em>= the number of quarters.

Then, we have three equations with four unknowns:

(1) <em>w</em> + <em>x = y </em>

(2) 3<em>w</em> = 2<em>z</em>

(3) 2<em>y</em> = 3<em>z</em>

However, there is a fourth <em>unstated </em>condition: <em>w</em>, <em>x</em>, y, and <em>z</em> must all be integers.

Assume that z = 6 (to avoid fractions).

From Equation (2), w = 4.

From Equation (3), y = 9.

Insert the values for <em>w</em> and <em>y</em> into equation (1).

4 + <em>x</em> = 9

x = 9 – 4 = 5

Thus, there are 4 pennies, 5 nickels, 9 dimes, and 6 quarters.

<em>Check</em>: 4 pennies + 5 nickels = 9 dimes

6 quarters + 4 pennies = 3 quarters for every 2 pennies

9 dimes + 6 quarters = 3 dimes for every 2 quarters

5 0
3 years ago
Read 2 more answers
Please help me:)))))
34kurt
It was done correctly
7 0
3 years ago
Read 2 more answers
Express 405 1/3 in simplest radical form.
Maslowich

Answer:

3 cube root of 15

Step-by-step explanation:

theres your simple radical form

4 0
2 years ago
For each value of U, determine whether it is a solution,
abruzzese [7]
Given u/7 - 1 = 7 and plugging in values for u,

For u = 28; 28/7 - 1 = 4 - 1 = 3; No
For u = -49; -49/7 - 1 = -7 - 1 = -8; No
For u = 42; 42/7 - 1 = 6 - 1 = 5; No
For u = 0; 0/7 - 1 = -1; No

Another way to find out which value would be a solution to u/7 - 1 = 7 is to solve for u.

u/7 - 1 = 7
u/7 = 7 + 1
u/7 = 8
u = 8*7
u = 56

The only solution to this equation is when u = 56.
8 0
3 years ago
Answer asap please thanks
Bad White [126]

missing number is 8. there is a pattern with the input and output numbers.

5 0
3 years ago
Read 2 more answers
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