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2 years ago

Find the area.........

Mathematics

1 answer:

rodikova [14]2 years ago

3 0

Answer:

211 cm

Step-by-step explanation:

upper rectangle + lower rectangle (11-8=3) + end triangles

(8x20) + (3x12) + (1/2x3x5 each x2)

160+36+15=211

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The area of rectangular field is (49m2-42m+9).Find the dimensions of the field

Drupady [299]

Answer:

The dimensions are (7m-3) by (7m-3)

Step-by-step explanation:

We have the area of the rectangular field to be:

$49 {m}^{2} - 42m + 9$

We need to factorize this expression.

Let us rewrite to obtain:

${(7m)}^{2} - 2(7 \times 3)m + {3}^{2}$

We can easily see that the expression is actually a perfect square trinomial.

This gives us:

$(7m - 3)^{2}$

$(7m - 3)(7m - 3)$

6 0

2 years ago

On a coordinate plane, a curved line with a minimum value of (negative 2.5, negative 12) and a maximum value of (0, negative 3)

goldfiish [28.3K]

Answer:

f(x) > 0 over the interval $(-\infty,-4)$

Step-by-step explanation:

If f(x) is a continuous function, and that all the critical points of behavior change are described by the given information, then we can say that the function crossed the x axis to reach a minimum value of -12 at the point x=-2.5, then as x increases it ascends to a maximum value of -3 for x = 0 (which is also its y-axis crossing) and therefore probably a local maximum.

Then the function was above the x axis (larger than zero) from $- \infty$ , until it crossed the x axis (becoming then negative) at the point x = -4. So the function was positive (larger than zero) in such interval.

There is no such type of unique assertion regarding the positive or negative value of the function when one extends the interval from $- \infty$ to -3, since between the values -4 and -3 the function adopts negative values.

6 0

2 years ago

Read 2 more answers

A soccer ball is kicked from 3 feet above the ground. the height,h, in feet of the ball after t seconds is given by the function

dexar [7]

Here's our equation.

$h=-16t+64t+3$

We want to find out when it returns to ground level (h = 0)

To find this out, we can plug in 0 and solve for t.

$0 = -16t+64t+3 \\ 16t-64t-3=0 \\ use\ the\ quadratic\ formula\ \frac{-b\±\sqrt{b^2-4ac}}{2a} \\ \frac{-(-64)\±\sqrt{(-64)^2-4(16)(-3)}}{2*16} = \frac{64\±\sqrt{4096+192}}{32}$

$= \frac{64\±\sqrt{4288}}{32} = \frac{64\±8\sqrt{67}}{32} = \frac{8\±\sqrt{67}}{4} = \boxed{\frac{8+\sqrt{67}}{4}\ or\ 2-\frac{\sqrt{67}}{4}}$

So the ball will return to the ground at the positive value of $\boxed{\frac{8+\sqrt{67}}{4}}$ seconds.

What about the vertex? Simple! Since all parabolas are symmetrical, we can just take the average between our two answers from above to find t at the vertex and then plug it in to find h!

$\frac{1}2(\frac{8+\sqrt{67}}{4}+2-\frac{\sqrt{67}}{4}) = \frac{1}2(2+\frac{\sqrt{67}}{4}+2-\frac{\sqrt{67}}{4}) = \frac{1}2(4) = 2$

$h=-16t^2+64t+3 \\ h=-16(2)^2+64(2)+3 \\ \boxed{h=67}$

8 0

3 years ago

Day, everything at a store is on sale. The store offers a 20% discount.

Nutka1998 [239]

Answer:

$14.40

Step-by-step explanation:

$18-20%=$14.40

4 0

2 years ago

What is the correct way to check the solved equation<br> 4,127÷3=1,375 remainder 2<br>

Dafna11 [192]

the quickest way to do this would be to multiply 1,375 by 3 and then add 2.

1,375 * 3 = 4,125 + 2 = 4,127

correct!

6 0

2 years ago

Read 2 more answers