Answer:
Given
f(x)=18,000(.88)^x
We need to find the value of x when f(x) <2000
2000 = 18000(0.88)^x
0.88^x 2000/18000
0.88^x 1/9
• x = log (1/9) / log (0.88)
• x= 17 (rounded down)
After 17 years or during year 18 the car value will drop below $2000
Answer:
P is exactly 3km east from the oil refinery.
Step-by-step explanation:
Let's d be the distance in km from the oil refinery to point P. So the horizontal distance from P to the storage is 3 - d and the vertical distance is 2. Hence the diagonal distance is:

So the cost of laying pipe under water with this distance is

And the cost of laying pipe over land from the refinery to point P is 400000d. Hence the total cost:

We can find the minimum value of this by taking the 1st derivative and set it to 0

We can move the first term over to the right hand side and divide both sides by 400000


From here we can square up both sides






d = 3
So the cost of pipeline is minimum when P is exactly 3km east from the oil refinery.
If this is a actual question then you are missing parts of it! Please leave a comment with the full question and I would be glad to help you out! If looking at what is given then 0 apples as all that is stated is only 48 oranges and no apples.
Answer:
I think the answer may be 0.05.
Step-by-step explanation:
This may be incorrect, but I hope it helps ^-^