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Kazeer [188]
3 years ago
8

Use long division to find the quotient below. (6x^3 - 29x^2 + 32x-14) ÷(2x-7)​

Mathematics
1 answer:
Andrej [43]3 years ago
4 0

Answer:

3x^2-4x+2

Step-by-step explanation:

Just took it

Trust me

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Use cross products to demonstrate whether the two ratios are equivalent in this problem: 4 over 6 times 14 over 21
ExtremeBDS [4]
4/6 = 14/21 When using cross product always multiply the left fractions numerator times the right side fractions denominator and the left side fractions denominator times the right side fractions numerator 4×21 = 6×14 84=84 They are equivalent because they both equal 84
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3 years ago
What is dynamic environment?​
jeka94

Answer:

A dynamic environment is a business environment that is rapidly changing. In a dynamic market, businesses have to adapt quickly to changes and develop new ideas, products and services to keep up with technology and new trends.

Step-by-step explanation:

6 0
2 years ago
F. one die is rolled 3 times. what is the chance of getting no 2's?
aniked [119]
6^3 = 216. When using chance, take the number of outcomes(six for a die) and raise it to the power of the number of repetitions 
6 0
3 years ago
Maggie is rock climbing. After reaching the summit, she descends 14 feet in 2 1/3 minutes. If she continues at this rate, where
attashe74 [19]
Steps:
2 1/3 * 3 = 7
14 * 3 = 42
42 divided by 7 = 6
6 * 8 = 48
So, Maggie is 48 feet under the summit (-48). Therefore, the correct answer is d.
4 0
3 years ago
Find the exact values of a) sec of theta b)tan of theta if cos of theta= -4/5 and sin<0
Gre4nikov [31]

Answer:

Using trigonometric ratio:

\sec \theta = \frac{1}{\cos \theta}

\tan \theta = \frac{\sin \theta}{\cos \theta}

From the given statement:

\cos \theta = -\frac{4}{5} and sin < 0

⇒\theta lies in the 3rd quadrant.

then;

\sec \theta = \frac{1}{-\frac{4}{5}} = -\frac{5}{4}

Using trigonometry identities:

\sin \theta = \pm \sqrt{1-\cos^2 \theta}

Substitute the given values we have;

\sin \theta = \pm\sqrt{1-(\frac{-4}{5})^2 } =\pm\sqrt{1-\frac{16}{25}} =\pm\sqrt{\frac{25-16}{25}} =\pm \sqrt{\frac{9}{25} } = \pm\frac{3}{5}

Since, sin < 0

⇒\sin \theta = -\frac{3}{5}

now, find \tan \theta:

\tan \theta = \frac{\sin \theta}{\cos \theta}

Substitute the given values we have;

\tan \theta = \frac{-\frac{3}{5} }{-\frac{4}{5} } = \frac{3}{5}\times \frac{5}{4} = \frac{3}{4}

Therefore, the exact value of:

(a)

\sec \theta =-\frac{5}{4}

(b)

\tan \theta= \frac{3}{4}

7 0
3 years ago
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