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Ghella [55]
3 years ago
10

Decide if there is one solution, no solution or infinitely many solutions. ½(6t – 4) = 3t - 4 *

Mathematics
2 answers:
ozzi3 years ago
8 0

Answer:

no solution, because there is no value of x.

Step-by-step explanation:

3t - 2 = 3t - 4

3t - 3t = 2 - 4

0 = -2

earnstyle [38]3 years ago
6 0

Answer:

Step-by-step explanation:

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c

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they have to have the same slope to be parallel

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A color printer prints 16 pages in 7 minutes.<br> How many pages does it print per minute?
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The printer can print 2.28 pages a minute. So 2
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SOMEBODY HELP PLEASEEE I DONT KNOW WHY THIS IS SUPPOSED TO BE 20+ CHARACTERS LONG BUT HERE IT IS
dimaraw [331]

<u>Answer:</u>

20h + 20

<u>Step-by-step explanation:</u>

5(2h + 4) + 10h

1️⃣ Expand by distributing terms.

<em>10h + 20 + 10h</em>

2️⃣ Collect like terms.

<em>(10h + 10h) + 20</em>

3️⃣ Simplify.

<em>20h + 20</em>

Answer: <em>20h + 20</em>

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6 0
3 years ago
A small garden measures 9 ft by 13 ft. A uniform border around the garden increases the total area to 192 ft square. What is the
victus00 [196]

The width of border is 1.5 feet

<h3><u>Solution:</u></h3>

Given that small garden measures 9 ft by 13 ft

A uniform border around the garden increases the total area to 192 ft square

To find: width of border

Let the width of border be "x"

Then the new measures of garden are (9 + 2x) feet and (13 + 2x) feet

The total area of garden = 192 square feet

(9 + 2x)(13 + 2x) =192

117 + 18x + 26x + 4x^2 = 192\\\\4x^2 + 44x - 75 = 0

<em><u>Let us solve the above equation by quadratic formula</u></em>

\text {For a quadratic equation } a x^{2}+b x+c=0, \text { where } a \neq 0\\\\x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}

Using the above formula,

For 4x^2 + 44x - 75 = 0 , we have a = 4 ; b = 44 ; c = -75

Substituting the values of a = 4 ; b = 44 ; c = -75 in above quadratic formula we get,

\begin{aligned}&x=\frac{-44 \pm \sqrt{44^{2}-4(4)(-75)}}{2 \times 4}\\\\&x=\frac{-44 \pm \sqrt{1936-1200}}{8}\\\\&x=\frac{-44 \pm \sqrt{3136}}{8}\\\\&x=\frac{-44 \pm 56}{8}\end{aligned}

\begin{aligned}&x=\frac{-44+56}{8} \text { or } x=\frac{-44-56}{8}\\\\&x=\frac{12}{8} \text { or } x=\frac{-100}{8}\\\\&x=1.5 \text { or } x=-12.5\end{aligned}

Since "x" cannot be negative,

we get x = 1.5

Thus width of border is 1.5 feet

4 0
3 years ago
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