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2 years ago

100 POINTS!!! ONLY 1 QUESTION! WILL GIVE BRAINLIEST. Please EXPLAIN how you got the answer

Mathematics

2 answers:

77julia77 [94]2 years ago

5 0

Answer:

Step-by-step explanation:

its hard to explain but pretty much if you didn't know the ^x+1 is the x intercept except when its graphed its no marked at (1,0) its mark ate (-1,0) because it always takes the inverse

if you go over to the right 3 then your adding 3 to the x intercept or subtracting 3 from ^x+1 so it would be ^x-2

the y intercept part is easy all you have to do is subtract 2 from the y intercept so it would be +2

hope this helps :D

Levart [38]2 years ago

3 0

Answer:

yes equation A is your answer

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How do you find the total sum of squared values?

tester [92]

Answer:

Step-by-step explanation:

$\sum^{12}_{r=1} r^2 = \frac{12(12+1)(2*12+1)}{6}= A$

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7 0

2 years ago

Suppose that 15% of the fields in a given agricultural area are infested with the sweet potato whitefly. One hundred fields in t

hram777 [196]

Answer:

a. $\mu=15$

b. $\mu=7.8586 \ and \ \mu=22.1414$

c. Choice A- Based on limits above, it is unlikely that we would see x = 45, so it might be possible that the trials are not independent.

Step-by-step explanation:

a.Binomial distribution is defined by the expression

$P(X=k)=C_k^n.p^k.(1-p)^{n-k}$

Let n be the number of trials, $n=100$

and p be the probability of success, $p=15\%$

The mean of a binomial distribution is the probability x sample size.

$\mu=np=100\times0.15=15$

b.Limits within which p is approximately 95%

sd of a binomial distribution is given as: $\sigma=\sqrt npq\\q=1-p$

Therefore, $\sigma=\sqrt(100\times0.015\times0.85)=3.5707$

Use the empirical rule to find the limits. From the rule, approximately 95% of the observations are within to standard deviations from mean.

$sd_1=>\mu-2\sigma=15-2\times3.3507=7.8586\\sd_2=>\mu-2\sigma=15+2\times3.3507=22.1414$

Hence, approximately 95% of the observations are within 7.8586 and 22.1414 (areas of infestation).

c. $x=45$ is not within the limits in b above (7.8586,22.1414). X=45 appears to be a large area of infestation. A.Based on limits above, it is unlikely that we would see x = 45, so it might be possible that the trials are not independent.