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Naya [18.7K]
3 years ago
15

PLEASE RIGHT ANSWERS ONLY!!

Mathematics
1 answer:
Temka [501]3 years ago
4 0

Answer

8

Step-by-step explanation:

algebra ll

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A painting is shaped like a golden rectangle. It's length is 24 cm. What is the paintings width to the nearest tenth of a cm?
olya-2409 [2.1K]
It depends if 24cm is the long dimension or the short one...it's the answer if 24cm is the short dim.
if 24cm is the long dimension then the answer is
24/1.618
6 0
4 years ago
the perimeter of a square is 20 ft if you increase the length of the square by 2 feet and decrease the width by 1ft what is the
IrinaVladis [17]

Answer:

28 ft squared

Step-by-step explanation:

The 4 sides of a square are equal in length, so if the perimeter is 20ft that means each side would have to be 5ft, (20/4 = 5). If you increase the length by 2ft, one of the sides would now become 7ft (5+2 = 7). If you decrease the length of the other side by 1ft, the length would now be 4ft (5-1=4). Now to find the area, all you have to do is length * width. So you would do 7ft*4ft which is 28ft squared.

4 0
4 years ago
Jenny bought a 5 notebooks and 2 pencils, and the total was 9 dollars.
weeeeeb [17]
You would solve this with simultaneous equations, so if we write it as:
5n + 2p = 9
3n + 2p = 6
(subtract)
2n = 3
÷ 2
notebooks = 1.5

Now you would substitute it in:
(3 × 1.5) + 2p = 6
4.5 + 2p = 6
- 4.5
2p = 1.5
÷ 2
pens = 0.75

So your final answer is notebooks are $1.50 and pens are $0.75, I hope this helps!
6 0
4 years ago
An electronics store is selling car chargers for cell phones. The expense function is E = - 300p + 13, 000 and the revenue funct
Brums [2.3K]

Answer:

Wala akong pake kasi ndi naman ako marunong sa math

5 0
3 years ago
Kara did a survey to determine to study the types of pets that students in her school had. She surveyed 300 students and found t
julsineya [31]

Answer:

(C)81

Step-by-step explanation:

Total Number of Students =300

Percentage who had cats, n(C) = 40%

Percentage who had both cats and dogs , n(C \cap D) = 12%

Percentage who had neither cats nor dogs, n(C \cup D)' =45%

Now:

Universal Set, U = n(C)+n(D)-n(C \cap D)+n(C \cup D)'

100 = 40 + n(D)-12+45\\n(D)=100-73\\$Percentage of those who own dogs =27\%

Therefore:

Number of Students who had dogs

=27% of 300

=81

3 0
3 years ago
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