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3 years ago

The temperature today will be atleast 10F | on a graph and inequality

Mathematics

1 answer:

viva [34]3 years ago

6 0

Answer:

Temperature => 10F

Step-by-step explanation:

Mark brainliest if this helped!

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a submarine travels 90 kilometers in 4 hours find the submarines rate of speed in kilometers per hour

defon

Answer:

22.5

Step-by-step explanation:

To find the rate of speed per hour, you need to divide the kilometer (90) by the hours (4).

90/4=

22.5

6 0

3 years ago

I don't know how to do this it is hard

Solnce55 [7]

(-4) means that it would be +4

3 0

3 years ago

Plz HELPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP

steposvetlana [31]

Answer:

36 ÷ a

55 - b

18 + c

49 x d

e ÷ 62

Step-by-step explanation:

7 0

3 years ago

1. Consider the rational numbers 4/13 and 3/10.

Murljashka [212]

A)4/13 would be the larger number since if you were to try to add them, 4/13 = 40/130 and 3/10 = 39/130, 40/130 > 39/130

B) A rational number between them would be 39.5/130.

5 0

3 years ago

Find the (a) mean, (b) median, (c) mode, and (d) midrange for the data and then (e) answer the given question. Listed below

mafiozo [28]

Answer:

a) $\bar X = 369.62$

b) $Median=175$

c) $Mode =450$

With a frequency of 4

d) $MidR= \frac{Max +Min}{2}= \frac{49+3000}{2}= 1524.5$

<u>e)</u> $s = 621.76$

And we can find the limits without any outliers using two deviations from the mean and we got:

$\bar X+2\sigma = 369.62 +2*621.76 = 1361$

And for this case we have two values above the upper limit so then we can conclude that 1500 and 3000 are potential outliers for this case

Step-by-step explanation:

We have the following data set given:

49 70 70 70 75 75 85 95 100 125 150 150 175 184 225 225 275 350 400 450 450 450 450 1500 3000

Part a

The mean can be calculated with this formula:

$\bar X = \frac{\sum_{i=1}^n X_i}{n}$

Replacing we got:

$\bar X = 369.62$

Part b

Since the sample size is n =25 we can calculate the median from the dataset ordered on increasing way. And for this case the median would be the value in the 13th position and we got:

$Median=175$

Part c

The mode is the most repeated value in the sample and for this case is:

$Mode =450$

With a frequency of 4

Part d

The midrange for this case is defined as:

$MidR= \frac{Max +Min}{2}= \frac{49+3000}{2}= 1524.5$

Part e

For this case we can calculate the deviation given by:

$s =\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}$

And replacing we got:

$s = 621.76$

And we can find the limits without any outliers using two deviations from the mean and we got:

$\bar X+2\sigma = 369.62 +2*621.76 = 1361$

And for this case we have two values above the upper limit so then we can conclude that 1500 and 3000 are potential outliers for this case

5 0

3 years ago