Following rules of logs, we can do the following:
log x^4 - log y^(1/2) + log z^3
Combine the first and 3rd factors to get log [x^4*z^3]
Seeing that the neg. sign signifies division, write this new term - log y^(1/2) as a quotient:
[x^4*z^3]
log ----------------
y^(1/2)
Next time, please include the instructions when you present your problem.
Thx.
Answer:
i)W = 2500 / T
ii) W = 500 Tons
iii) grad W(10°) = - 25î
iv) The formulation is not practical
Step-by-step explanation:
i) Write an equation describing the use of coal
As use of coal is inversely proportional to the average monthly temperature
if W is use of coal in tons/per month then
W(t) = k / T where k is a constant of proportionality and T is the average temperature in degrees. We have to determine k from given conditions
k = ?? we know that when T = 25° W = 100 tons the by subtitution
W = k/T 100 = k /25 k = 2500 Tons*degree
Then final equation is:
W = 2500 / T
ii) Find the amount of coal when T = 5 degrees
W = 2500 / 5
W = 500 Tons
iii)
The inverse proportionality implies that W will decrease as T increase.
The vector gradient of W function is:
grad W = DW(t)/dt î
grad W = - 2500/T² î
Wich agrees with the fact that W is decreasing.
And when T = 100°
grad W(10°) = - 2500/ 100 î ⇒ grad W(10°) = - 25î
iv) When T = 0 The quantity of coal tends to infinite and the previous formulation is not practical
You have to build an equation to find the answer,
angles in a straight line add upto 180°
so your equation would be,
12x+30°=180°
-30 -30
=12x=150°
÷12 ÷12
=x=12.5°
now find the measures of the angles by using 12.5 as x.
angle EAF= 2x
=2×12.5
=25° degrees
angle DAE= 4x
=4×12.5
=50°degrees
angle CAD=6x
=6×12.5
=75°degrees
check,
30+25+50+75=180°degrees
hope this helps.......
V=hpir^2
r=2
h=5
pi≈3.141592
v=5*3.141592*2^2
v=5*3.141592*4
v=20*3.141592
v=62.83185307179586476925286766559
round to tenth
62.8 cubic units
Answer:
-17
Step-by-step explanation:
- -3 - 14 = -17
I hope this helps!
