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sergij07 [2.7K]
3 years ago
10

Solve the system using elimination. 5x + 3y = − 8 7x + 2y = − 20

Mathematics
1 answer:
svlad2 [7]3 years ago
3 0
Your answer should be (-4,4). You would multiply the top row by 2 and the bottom one by -3 to get the y’s the same (both would be 6y) then from there solve for x. once you have x plug in for y.
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6 0
4 years ago
What are the possible rational zeros of f(x) = x4 − 4x3 + 9x2 + 5x + 14?
Dovator [93]

Answer:

±1, ±2, ±7, ±14

Step-by-step explanation:

6 0
3 years ago
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Soloha48 [4]

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4 0
3 years ago
Find a polynomial function of degree 3 with 2, i, -i as zeros.
sergiy2304 [10]

Answer:

p(x)= x^3-2x^2+x-2

Step-by-step explanation:

Here we are given that a polynomial has zeros as 2 , i and -i . We need to find out the cubic polynomial . In general we know that if \alpha , \ \beta \ \& \ \gamma are the zeros of the cubic polynomial , then ,

\sf \longrightarrow p(x)= (x -\alpha )(x-\beta)(x-\gamma)

Here in place of the Greek letters , substitute 2,i and -i , we get ,

\sf\longrightarrow p(x)= (x -2 )(x-i)(x+i)

Now multiply (x-i) and (x+i ) using the identity (a+b)(a-b)=a² - b² , we have ,

\sf  \longrightarrow p(x)= (x-2)\{ x^2 - (i)^2\}

Simplify using i = √-1 ,

\sf \longrightarrow p(x)= (x-2)( x^2 + 1 )

Multiply by distribution ,

\sf \longrightarrow p(x)= x(x^2+1) -2(x^2+1)

Simplify by opening the brackets ,

\sf\longrightarrow p(x)= x^3+x-2x^2-2

Rearrange ,

\sf\longrightarrow \underline{\boxed{\blue{\sf p(x)= x^3-2x^2+x-2}}}

4 0
3 years ago
What is the LEAST possible integer value and the greatest
vagabundo [1.1K]

Answer:

hey mate I guess ur question is incomplete......after greatest what is it? plz check

8 0
3 years ago
Read 2 more answers
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