You said that (xy) = 16, and (x+y) = 4 .
From the second equation you can get [ x = 4 - y ],
then substitude that for 'x' in the first equation, and
finally, rearrange the first equation to read
<u>x² - 4x + 16 = 0</u>
Don't even try to factor that quadratic equation. Go straight
to the quadratic formula, and the two solutions you find are ...
<em>x = 2 + i 2√3</em>
and
<em>x = 2 - i 2√3</em> .
Those are the two number that do what you want.
There are no <u>real</u> numbers that can do it.
Step-by-step explanation:
Given
( 6x² - x + 8 ) - ( x² + 2)
= 6x² - x + 8 - x² - 2
= 5x² - x + 6
Answer:
Step-by-step explanation:
8=16+8n
8-16=16-16+8n
-8=8n
-8/8=8n/8n
-1=n
Answer:
SAS
Step-by-step explanation:
SAS Postulate: "If two sets of corresponding sides on two triangles and there included angle are congruent, then the triangles are similar".
We see that line segments XY-ST and XZ-SR are congruent along with the included angles X and S. Therefore, we can justify that SAS fits the situation.
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