Zero property is going to be your answer
You have two equations.
since the second is already isolated, sub in x-4 for every y in equation 1 so that
![x^{2} - 4 [(x-4)^{2}] =16 ](https://tex.z-dn.net/?f=%20x%5E%7B2%7D%20-%204%20%5B%28x-4%29%5E%7B2%7D%5D%20%3D16%0A%20)
expand, collect like terms, factor to find x, then plug x value back into original equation to find y
Thanks for the free points <33333
Answer:
949
Step-by-step explanation:
If the 3 digit number is rounded to 900, then this number is between 900 and 950.
The digit in the ones place is the fifth odd number begginning with 1, so this number is number 9.
Lastly, the sum of digits is 22.
Putting our number as 9x9, where x is the tens digit, we know that 9 + x + 9 = 22, so we have that x = 4
So, our number is 949