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adell [148]
3 years ago
11

Describe the polynomial 2x^3+x+5

Mathematics
1 answer:
tankabanditka [31]3 years ago
4 0

Answer:

2x^3 + 0x^2 + 1x^1 +5 ( in terms of coefficient)

it will have 3 roots......

it has degree 3 and is a cubic polynomial...

it will touch 3 points in x-axis while plotting this polynomial in graph

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Mashcka [7]

Answer:b

10 to 20 is 10 and 80 to 60 is -20 so it’s -20/10 which is -2

7 0
3 years ago
What is the surface area of a cylinder with a diameter of 8 and a height of 18?Express the answer in terms of pi
viktelen [127]

Step-by-step explanation:

diameter: 8

radius: 4

height: 18

A=2\pi rh+2\pi r^2\\A=2\pi(4)(18)+2\pi(4)^2\\A=2\pi(72)+2\pi(16)\\A=144\pi+32\pi\\A=176\pi

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4 years ago
Task 1 Nonlinear Systems of Equations Create a system of equations that includes one linear equation and one quadratic equation.
Luden [163]

Answer:

hope this helps

Step-by-step explanation:

solution:

x^2 + 3x + 5 = x + 13

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4 0
3 years ago
Prove by mathematical induction that 1+2+3+...+n= n(n+1)/2 please can someone help me with this ASAP. Thanks​
Iteru [2.4K]

Let

P(n):\ 1+2+\ldots+n = \dfrac{n(n+1)}{2}

In order to prove this by induction, we first need to prove the base case, i.e. prove that P(1) is true:

P(1):\ 1 = \dfrac{1\cdot 2}{2}=1

So, the base case is ok. Now, we need to assume P(n) and prove P(n+1).

P(n+1) states that

P(n+1):\ 1+2+\ldots+n+(n+1) = \dfrac{(n+1)(n+2)}{2}=\dfrac{n^2+3n+2}{2}

Since we're assuming P(n), we can substitute the sum of the first n terms with their expression:

\underbrace{1+2+\ldots+n}_{P(n)}+n+1 = \dfrac{n(n+1)}{2}+n+1=\dfrac{n(n+1)+2n+2}{2}=\dfrac{n^2+3n+2}{2}

Which terminates the proof, since we showed that

P(n+1):\ 1+2+\ldots+n+(n+1) =\dfrac{n^2+3n+2}{2}

as required

4 0
3 years ago
Pls helpp im failing
nydimaria [60]

Answer:

-41.6

Step-by-step explanation:

6 0
3 years ago
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