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2 years ago

Describe the polynomial 2x^3+x+5

Mathematics

1 answer:

tankabanditka [31]2 years ago

4 0

Answer:

2x^3 + 0x^2 + 1x^1 +5 ( in terms of coefficient)

it will have 3 roots......

it has degree 3 and is a cubic polynomial...

it will touch 3 points in x-axis while plotting this polynomial in graph

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Stella [2.4K]

Answer:

Shesh

Step-by-step explanation:

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2 years ago

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I don’t know how to make a rule:(

Yuri [45]

Answer:

*assuming you know the concept of proportionality*

since L is directly proportional to T, an increase in L will result in an increase in T

so the solution of the first part is increases

in part 2, y is inversely proportional to x

which means that an increase in y will result in a decrease in x and vice-versa

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3 years ago

What is the surface of a cylinder radius 8mm height of 20 mm

LiRa [457]

Hey there :) You'll have to use the formula of cylinder to get your answer :
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pi = 22.7 or 22/7
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h = height of cylinder = 20mm

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2 years ago

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kakasveta [241]

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2 years ago

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Each year, all final year students take a mathematics exam. It is hypothesised that the population mean score for this test is 1

Yuri [45]

Answer:

90% confidence interval for the population mean test score is [95.40 , 106.59]

Step-by-step explanation:

We are given that the population mean score for mathematics test is 115. It is known that the population standard deviation of test scores is 17.

Also, a random sample of 25 students take the exam. The mean score for this group is 101.

The, pivotal quantity for 90% confidence interval for the population mean test score is given by;

P.Q. = $\frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, X bar = sample mean = 101

$\sigma$ = population standard deviation

n = sample size = 25

So, 90% confidence interval for the population mean test score, $\mu$ is ;

P(-1.6449 < N(0,1) < 1.6449) = 0.90

P(-1.6449 < $\frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } }$ < 1.6449) = 0.90

P(-1.6449 * $\frac{\sigma}{\sqrt{n} }$ < ${Xbar-\mu}$ < 1.6449 * $\frac{\sigma}{\sqrt{n} }$ ) = 0.90

P(X bar - 1.6449 * $\frac{\sigma}{\sqrt{n} }$ < $\mu$ < X bar + 1.6449 * $\frac{\sigma}{\sqrt{n} }$ ) = 0.90

90% confidence interval for $\mu$ = [ X bar - 1.6449 * $\frac{\sigma}{\sqrt{n} }$ , X bar + 1.6449 * $\frac{\sigma}{\sqrt{n} }$ ]

= [ 101 - 1.6449 * $\frac{17}{\sqrt{25} }$ , 10 + 1.6449 * $\frac{17}{\sqrt{25} }$ ]

= [95.40 , 106.59]

Therefore, 90% confidence interval for the population mean test score is [95.40 , 106.59] .

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3 years ago