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pshichka [43]
3 years ago
15

A rectangle is shown. What is the area of the rectangle?

Mathematics
2 answers:
mixas84 [53]3 years ago
4 0

Answer:

360

Step-by-step explanation:

15+15

12x15

Reika [66]3 years ago
4 0

ANSWER:

360

Step-by-step explanation:

15+15

12x15

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F(x) = x2 + 2x-5<br> g(x) = -3/2 - 4x + 1<br> What is f(x) – g(x)?
NeX [460]

Step-by-step explanation:

Start by finding (fog)(x)

To find this function, substitute x=

x−1

4

That is g(x) into f(x)

⇒(f∘g)(x)=(

x−1

4

)

2

−2(

x−1

4

)+5

=

(x−1)

2

16

−

x−1

8

+5

Now substitute x=3

⇒(f∘g)(3)=

(3−1)

2

16

−

3−1

8

+5

=

4

16

−

2

8

+5=4−4+5=5.

Hope it helps:)

6 0
3 years ago
Prove that if {x1x2.......xk}isany
Radda [10]

Answer:

See the proof below.

Step-by-step explanation:

What we need to proof is this: "Assuming X a vector space over a scalar field C. Let X= {x1,x2,....,xn} a set of vectors in X, where n\geq 2. If the set X is linearly dependent if and only if at least one of the vectors in X can be written as a linear combination of the other vectors"

Proof

Since we have a if and only if w need to proof the statement on the two possible ways.

If X is linearly dependent, then a vector is a linear combination

We suppose the set X= (x_1, x_2,....,x_n) is linearly dependent, so then by definition we have scalars c_1,c_2,....,c_n in C such that:

c_1 x_1 +c_2 x_2 +.....+c_n x_n =0

And not all the scalars c_1,c_2,....,c_n are equal to 0.

Since at least one constant is non zero we can assume for example that c_1 \neq 0, and we have this:

c_1 v_1 = -c_2 v_2 -c_3 v_3 -.... -c_n v_n

We can divide by c1 since we assume that c_1 \neq 0 and we have this:

v_1= -\frac{c_2}{c_1} v_2 -\frac{c_3}{c_1} v_3 - .....- \frac{c_n}{c_1} v_n

And as we can see the vector v_1 can be written a a linear combination of the remaining vectors v_2,v_3,...,v_n. We select v1 but we can select any vector and we get the same result.

If a vector is a linear combination, then X is linearly dependent

We assume on this case that X is a linear combination of the remaining vectors, as on the last part we can assume that we select v_1 and we have this:

v_1 = c_2 v_2 + c_3 v_3 +...+c_n v_n

For scalars defined c_2,c_3,...,c_n in C. So then we have this:

v_1 -c_2 v_2 -c_3 v_3 - ....-c_n v_n =0

So then we can conclude that the set X is linearly dependent.

And that complet the proof for this case.

5 0
3 years ago
PLEASE HELP ME WITH THE QUESTION IN THE PICTURE BELOW
Ber [7]
The correct answer is 24-2D...so you’re answer is D. And I’m also a kpop/Enhypen stan
8 0
3 years ago
Read 2 more answers
What is sin 0 when sec 0 = 5? 0 |(1,0) sin e = 2[?] [] Rationalize the denominator if necessary.​
Komok [63]

Answer:

Sin ~0 =\frac{2\sqrt{5} }{5}

Step-by-step explanation:

sec0=\sqrt{5}

cos~0=\frac{1}{sec0} =\frac{1}{\sqrt{5} }

sin ~0=\sqrt{1-cos^2~0}

=\sqrt{1-1/5}=\sqrt{5-1/5}

Sin~0=\sqrt{4/5} =2/\sqrt{5}*\sqrt{5}/\sqrt{5}

Sin~0=2\sqrt{5}/2=2\sqrt{5}/5

<u>--------------------------------</u>

hope it helps...

have a great day!!!

7 0
3 years ago
¿give me the answer please?
nevsk [136]

Answer:

the volume is 60 cm cubed

Step-by-step explanation:

(5 x 8) / 2 x 3

5 x 8 = 40

40 / 2 = 20

20 x  3 = 60

6 0
3 years ago
Read 2 more answers
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