the data represents the heights of fourteen basketball players, in inches. 69, 70, 72, 72, 74, 74, 74, 75, 76, 76, 76, 77, 77, 8
Daniel [21]
If you would like to know the interquartile range of the new set and the interquartile range of the original set, you can do this using the following steps:
<span>The interquartile range is the difference between the third and the first quartiles.
The original set: </span>69, 70, 72, 72, 74, 74, 74, 75, 76, 76, 76, 77, 77, 82
Lower quartile: 72
Upper quartile: 76.25
Interquartile range: upper quartile - lower quartile = 76.25 - 72 = <span>4.25
</span>
The new set: <span>70, 72, 72, 74, 74, 74, 75, 76, 76, 76, 77, 77
</span>Lower quartile: 72.5
Upper quartile: 76
Interquartile range: upper quartile - lower quartile = 76 - 72.5 = 3.5
The correct result would be: T<span>he interquartile range of the new set would be 3.5. The interquartile range of the original set would be more than the new set.</span>
Answer:
60cm²
Step-by-step explanation:
The area of a rhombus is: A=d1×d2/2, where d1 and d2 are its diagonals.
A=10×12/2=60cm²
Answer:
49°
Step-by-step explanation:
The given information that BC=DC tells you triangle BCD is an isosceles triangle and that angle y is one of the two equal base angles. Then ...
y + y + 82 = 180 . . . . . the sum of angle measures is 180 degrees
2y = 98 . . . . subtract 82
y = 49 . . . . . divide by 2
The measure of y is 49°.
The equation, y = -2x + 5, is not in standard form. The standard form of a linear line is ax + by = c. This equation is in slope - intercept form, which is y = mx + b.
