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3 years ago

Se tiene que pegar encaje aun aro de 35 centimetros de diametro¿Cuanto encaje se necesita para cubrirlo?

Mathematics

2 answers:

nalin [4]3 years ago

4 0

Cual es la formula?
cual es???

makvit [3.9K]3 years ago

4 0

Translation of this question "Se tiene que pegar encaje aun aro de 35 centimetros de diametro¿Cuanto encaje se necesita para cubrirlo? " in English is :

" It has to stick lace even ring of 35 centimeters in diameter How much lace is needed to cover it?"

That means we have to find how much lace is needed to cover ring having diameter of 35 centimeter.

In other words we need to find circumference of the ring.

Radius r = 35 centimeter

circumference of ring = D π =35 π

Hence final answer is 35 π centimeter.

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Which function has a vertex on the y-axis? f(x) = (x – 2)2 f(x) = x(x + 2) f(x) = (x – 2)(x + 2) f(x) = (x + 1)(x – 2)

strojnjashka [21]

we know that

If the vertex is on the y-axis, then the x-coordinate of the vertex is equal to zero

we are going to verify the vertex of each one of the functions to determine the solution

Remember that

The equation in vertex form of a vertical parabola is equal to

$y=a(x-h)^{2} +k$

where

(h,k) is the vertex

if $a>0$ -------> the parabola open upward (vertex is a minimum)

if $a$ -------> the parabola open downward (vertex is a maximun)

case A) $f(x)=(x-2)^{2}$

This is a vertical parabola open upward

the vertex is the point $(2,0)$

therefore

The function $f(x)=(x-2)^{2}$ does not have a vertex on the y-axis

case B) $f(x)=x(x+2)$

$f(x)=x(x+2)=x^{2}+2x$

convert to vertex form

Complete the square. Remember to balance the equation by adding the same constants to each side.

$f(x)+1=x^{2}+2x+1$

Rewrite as perfect squares

$f(x)+1=(x+1)^{2}$

$f(x)=(x+1)^{2}-1$

the vertex is the point $(-1,-1)$

therefore

The function $f(x)=x(x+2)$ does not have a vertex on the y-axis

case C) $f(x)=(x-2)(x+2)$

$f(x)=(x-2)(x+2)=x^{2}-2^{2}$

$f(x)=x^{2}-4$

the vertex is the point $(0,-4)$

The x-coordinate of the vertex is equal to zero

therefore

The function $f(x)=(x-2)(x+2)$ has a vertex on the y-axis

case D) $f(x)=(x+1)(x-2)$

$f(x)=(x+1)(x-2)\\ \\f(x)= x^{2}-2x+x-2 \\ \\f(x)= x^{2} -x-2$

convert to vertex form

Group terms that contain the same variable, and move the constant to the opposite side of the equation

$f(x)+2= x^{2} -x$

Complete the square. Remember to balance the equation by adding the same constants to each side.

$f(x)+2+0.25= x^{2} -x+0.25$

$f(x)+2.25= x^{2} -x+0.25$

Rewrite as perfect squares

$f(x)+2.25= (x-0.50)^{2}$

$f(x)=(x-0.50)^{2}-2.25$

the vertex is the point $(0.5,-2.25)$

therefore

The function $f(x)=(x+1)(x-2)$ does not have a vertex on the y-axis

the answer is

$f(x)=(x-2)(x+2)$

6 0

3 years ago

Read 2 more answers

Three times the sum of a number 2 is the same as the number minus 4. Find the number.

Natali [406]

Answer:the number is ten

Step-by-step explanation:

5 0

4 years ago

Workout the probability that spinner A lands on 2 and spinner b does not land on b

zzz [600]

Spinner diagram isn't attached. A related spinner diagram has been attached below to provide an hypothetical solution to the problem

Answer:

4 / 15

Step-by-step explanation:

For the numbered spinner :

P(landing on 2) = required outcome / Total possible outcomes

Total possible outcomes = (1, 2, 3) = 3

Required outcome = (1) = 1

P(landing on 2) = 1 /3

Lettered spinner :

P(does not land on b)

Total possible outcomes = (A, B, C, D, E)

Required outcome = (a, c, d, e)

P(does not land on b) = 4 / 5

Hence,

P(lands on 2, does not land on b) in this scenario is :

1/3 * 4/5 = 4 / 15

5 0

3 years ago

What is the slope of the line that passes through the points (-2,7) and (2,-5) in simplest form ?

creativ13 [48]

Its $m=\dfrac{\Delta y}{\Delta x}=\dfrac{7-(-5)}{-2-2}=\dfrac{12}{-4}=\boxed{-3}$ .

Hope this helps.

6 0

3 years ago

a farmer is buying fencing to surround a square field of area 3600m^2. What length of fencing does he need to buy?

kirill115 [55]

Answer:

240 m

Step-by-step explanation:

The area of a square field is 3600 m².

We need to find the length of fencing he needs to buy. It means we need to find the perimeter of the field.

The area of a square field is given by :

A = side²

So,

$s=\sqrt{3600} \ m\\\\s=60\ m$

Length of fencing = perimeter

= 4(s)

= 4(60)

= 240 m

So, he would need to buy 240 m of fencing.

8 0

3 years ago