set h=0 and solve for <span>t
</span>So: 0 = 32t - 16^2
<span>32t−16<span>t2</span>=0</span><span>16t(2−t)=0</span><span><span>t=2
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Answer:
c and d
Step-by-step explanation:
Answer:
8
Step-by-step explanation:
Since they intersect you can just solve for x and y
since y=-4x and y=x^2+2x+8, you can set -4x=x^2+2x+8
add 4x to both sides to make 0=x^2+6x+8
and factor out (x+4)(x+2)
so the solutions for x are -4 and -2
then insert the two values for x into the first equation
so y=-4(-4) and y=-4(-2)
so y=16 and y=8 when x=-4 and x=-2
so the smallest value for y in both equations is 8
Please give brainliest :)
Answer: 6 is the y intercept
Step-by-step explanation:
