What is the answers or is that what it gives you?
Answer:
0.483
Explanation:
The given population is in Hardy-Weinberg equilibrium. If the gene has two alleles, the sum total of the frequencies of these two alleles will be one.
Therefore, the total of the frequency of allele B and frequency of allele b will be 1. f(B) + f(b)=1
If the frequency of allele "B" is 0.59, then the frequency of allele "b" will be=1-0.59= 0.41
The frequency of heterozygous genotype in the population= 2pq
p= frequency of the dominant allele
q= frequency of the recessive allele
So, 2pq= 2 x 0.59 x 0.41 = 0.483
Answer:
I don't speak English, I only translate, I'm sorry, but you like Kunno, I know, hush, I said hush, I don't talk to Kunno fans
Answer:
genetics
Explanation:
calico cats must also inherit a gene unrelated to the X and Y chromosomes that codes for white fur. Because male cats have one X chromosome with code for black or orange and one Y chromosome with no color genes, they cannot technically be calico. About one in every 3,000 calico cats is born a male, and, unfortunately, don't live as long as female calicos due to their genetic abnormalities. XXY Syndrome renders male calicos sterile and can be the root cause of many other health problems
