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2 years ago

Which equation best represents the line? (4 points)

Mathematics

2 answers:

Bond [772]2 years ago

4 0

What line....??????????

zhuklara [117]2 years ago

4 0

We need to know what the line is

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* Find the area of a triangle: Base of 8 cm Hight of 9 cm

Sliva [168]

Answer:

36 cm

Step-by-step explanation:

The formula to find the area of a triangle is A=1/2bh where b stands for base and h for height.

So, 8 times 9 equals 72, and 72 divided by 2 is 36.

5 0

2 years ago

What is the correct domain for a log function? A=(-∞,0] B=[0,∞) C=(-∞,0) D=(0,∞)

masha68 [24]

$f(x)=\log(x)\\\\Domain:\\\\x > 0\to x\in(0,\ \infty)\\\\Answer:\ \boxed{D=(0,\ \infty)}$

3 0

2 years ago

Identify the equation in standard form of the line that passes through the point (6,−8) and has the slope of −2 .

Arturiano [62]

Answer:

y = -2x + 4

Step-by-step explanation:

y = -2x + b

-8 = -2(6) + b

-8 = -12 + b

4 = b

6 0

3 years ago

Suppose you do an analysis of the starting salaries of 100 recent Lehman graduates. You find that the average starting salary is

madreJ [45]

Answer:

a) (59180,60820)

b) (59020,60980)

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = $60,000

Standard Deviation, σ = $5,000

Sample size, n = 100

a) 90% critical values

$\mu \pm z_{critical}\frac{\sigma}{\sqrt{n}}$

Putting the values, we get,

$z_{critical}\text{ at}~\alpha_{0.10} = 1.64$

$60000 \pm 1.64(\frac{5000}{\sqrt{100}} ) = 60000 \pm 820 = (59180,60820)$

b) 95% critical values

$\mu \pm z_{critical}\frac{\sigma}{\sqrt{n}}$

Putting the values, we get,

$z_{critical}\text{ at}~\alpha_{0.05} = 1.96$

$60000 \pm 1.96(\frac{5000}{\sqrt{100}} ) = 60000 \pm 980= (59020,60980)$

5 0

2 years ago

a wire of length 200 cm is cut into two parts and each part is bent to form a square.If the area of the larger square is 9 times

diamong [38]

Answer:

The perimeter of the larger square is $150cm.$

Step-by-step explanation:

First of all, let one part of it be " $x$ "

and the other part of it " $200-x$ "

Now to solve this :

The area of the square = $L^2$

The area of one part of the square = $x^2$

The area of the other part of the square = $(200-x)^2$

$9x^2= (200-x)^2\\9x^2=40000-400x+x^2$

Now, add, $-4x^2$ to both the sides :

$9x^2-9x^2=40000-400x+x^2-9x^2\\-1(8x^2+400x-40000)=0$

Now, take out the "8" which is common :

$-8(x^2+50x-5000)=0$

Now, divide it by $-8$ :

$x^2+100x-50x-5000=0\\x(x+100)-50(x+100)=0\\(x+100)(x-50)=0\\$

$x=-100$ or $50$

So, now we know that :

One of the part is = $50cm$

And the other part is = $150cm$

Thus the perimeter of the larger square is = $150cm$

3 0

3 years ago