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andreev551 [17]
3 years ago
8

The spoke of a wheel reaches from the center of the wheel to its rim. If the circumference of the rim of the wheel is 48 inches,

how long is each spoke? Use 3.14 for π, and round your answer to the nearest hundredth.

Mathematics
1 answer:
aleksklad [387]3 years ago
4 0
Check the picture below

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Simplify the expression 7C4
Nady [450]
To simplify 7C4 we use the combination formula given by:
nCr=n!/[(n-r)!r!]
thus:
In our case we shall have:
n=7 and r=4
7C4
=7!/[(7-4)!4!]
=5040/[6×24]
=5040/144
=35

The answer is 35

6 0
3 years ago
Plsss help it due today I don’t understand how to do this plssss don’t just take the points
tensa zangetsu [6.8K]

Answer:

d a m i dont even know this

Step-by-step explanation:

4 0
3 years ago
As a recruiter, you are asked to recruit 65 new sales associates for an organization. Traditionally, for the organization, 25% o
Lorico [155]

Answer: 1733.33 ≈ 1734 applicants

Step-by-step explanation:

Let x be the number of job applicants being looked at.

If 25% of applicants become job candidates, then number of job candidates = 0.25x

If 20% of job candidates receive job offers, then the number of job offers = 0.20 × 0.25x = 0.05x

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This 0.0375x shows the number of new recruits which is equivalent to the 65 that is needed by the client if the recruiter.

By equating this 0.0375x to 65,we have:

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5 0
3 years ago
(−7³+8²−17+9)−(4³+5²−4+2)
gavmur [86]

Answer:

-374

Step-by-step explanation:

6 0
2 years ago
Read 2 more answers
The radius of a right circular cone is increasing at a rate of 4 inches per second and its height is decreasing at a rate of 5 i
solmaris [256]

Answer:

V' = 900\pi in^{3} /sec

Step-by-step explanation:

V = \frac{1}{3} \pi r^{2}h

V' = \frac{2\pi rh *r'}{3}  + \frac{\pi r^{2} *h'}{3} (using differentiation product rule)

plug known values in for r, h, r', and h'

V' = \frac{2\pi (10)(40)(4)}{3} + \frac{\pi (10^{2} )(-5)}{3}

V' = \frac{3200\pi }{3} - \frac{500\pi }{3} \\V' = \frac{2700\pi }{3} \\

V' = 900\pi in^{3} /sec

3 0
3 years ago
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