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mash [69]
3 years ago
10

10. Aman plans to spend his January salary as

Mathematics
1 answer:
julia-pushkina [17]3 years ago
6 0

Answer:

11828282828282838383838383838

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Lana has 3 bags with the same amount of marbles in them, totaling 12 marbles. Markus has 3 bags with the same amount of marbles
Julli [10]

Answer:

Markus has 6 marbles in each bag.

Step-by-step explanation:

Markus has 18 marbles and 3 bags

If you divide 18 marbles by 3 bags that would be 6 marbles in each bag.

5 0
3 years ago
PLEASE HELP AS SOON AS POSSIBLE WILL GIVE BRAINLIEST
allsm [11]

The answer and work is in the SS below

3 0
3 years ago
Read 2 more answers
A circle has the equation x^2+y^2+x-6y+9=0. Find the center and any x or y intercepts.
Softa [21]
We know:x^2+y^2+x−6y+9=0So, we complete the square as such:x^2+y^2+x−6y+9=x^2+x+y^2−6y+9=(x+1/2)^2+(y−3)^2=(1/2)^2=1/4
5 0
3 years ago
From a piece of tin in the shape of a square 6 inches on a side, the largest possible circle is cut out. What is the ratio of th
wel

Answer:

\sf \dfrac{1}{4} \pi \quad or \quad \dfrac{7}{9}

Step-by-step explanation:

The <u>width</u> of a square is its <u>side length</u>.

The <u>width</u> of a circle is its <u>diameter</u>.

Therefore, the largest possible circle that can be cut out from a square is a circle whose <u>diameter</u> is <u>equal in length</u> to the <u>side length</u> of the square.

<u>Formulas</u>

\sf \textsf{Area of a square}=s^2 \quad \textsf{(where s is the side length)}

\sf \textsf{Area of a circle}=\pi r^2 \quad \textsf{(where r is the radius)}

\sf \textsf{Radius of a circle}=\dfrac{1}{2}d \quad \textsf{(where d is the diameter)}

If the diameter is equal to the side length of the square, then:
\implies \sf r=\dfrac{1}{2}s

Therefore:

\begin{aligned}\implies \sf Area\:of\:circle & = \sf \pi \left(\dfrac{s}{2}\right)^2\\& = \sf \pi \left(\dfrac{s^2}{4}\right)\\& = \sf \dfrac{1}{4}\pi s^2 \end{aligned}

So the ratio of the area of the circle to the original square is:

\begin{aligned}\textsf{area of circle} & :\textsf{area of square}\\\sf \dfrac{1}{4}\pi s^2 & : \sf s^2\\\sf \dfrac{1}{4}\pi & : 1\end{aligned}

Given:

  • side length (s) = 6 in
  • radius (r) = 6 ÷ 2 = 3 in

\implies \sf \textsf{Area of square}=6^2=36\:in^2

\implies \sf \textsf{Area of circle}=\pi \cdot 3^2=28\:in^2\:\:(nearest\:whole\:number)

Ratio of circle to square:

\implies \dfrac{28}{36}=\dfrac{7}{9}

5 0
2 years ago
What is m _BEC<br> OB) 70°<br> OA) 65°<br> OD) 120°<br> OC) 50°
just olya [345]

Answer:

C) 50°

Step-by-step explanation:

m\angle BEC= 180\degree-(65\degree+65\degree)

\implies m\angle BEC= 180\degree-130\degree

\implies m\angle BEC= 50\degree

5 0
2 years ago
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