Ask question

Ask question

All categories

3 years ago

13

Compare 0.3 and 0.8 using >,=,or <. Draw a model or number line to support your solutions

1 answer:

Ghella [55]3 years ago

7 0

0.3 < 0.8. I can't do the #line on here tho. Sorry.

You might be interested in

Can someone help me ASAP!!

Lana71 [14]

The answer is 5.

Step-by-step explanation:

To find the interquartile range you must look at the median and the upper and lower halves of the data. The median (12) to the upper half of the data (15) is 3. Next, look at the median (12) to the lower half of the data (10) it is 2. We then add 2 and 3 to get the interquartile range of 5.

6 0

2 years ago

I need help on this question ASAP.

BigorU [14]

Answer:

C

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

I have 1,141 point i thought i might share them you here you go

zaharov [31]

Answer:

Thank you, person.

I hope this is good enough:

you want to talk about anything

7 0

3 years ago

How do i plot 3 points on a graph when all I am given is "x=4" ? and I need to find "x and y" for 3 points.

ipn [44]

Answer:

(4,-1) (4,0) (4,1)

Step-by-step explanation:

If you graph this, it will be a straight vertical line. No matter what y is, x will always be 4.

8 0

1 year ago

A car has mass 1500 kg and is traveling at a speed of 35 miles/hour. what is its kinetic energy in joules? (Be sure to convert m

photoshop1234 [79]

Answer:

Factor by which kinetic energy increase = 4 times

Step-by-step explanation:

Given,

Mass of the car, v1 = 1500 kg

initial speed of car = 35 miles/h

$=\dfrac{35\times 1609.34}{3600}\ m/s$

= 15.64 m/s

Initial kinetic energy of the car is given by,

$k_1\ =\ \dfrac{1}{2}.m.v_1^2$

$=\ \dfrac{1}{2}\times 1500\times (15.64)^2\ joule$

= 183606.46 J

Final velocity of car v2 = 70 miles/hour

$=\dfrac{70\times 1609.34}{3600}$

= 31.29 m/s

So, final kinetic energy of car is given by

$k_2\ =\ \dfrac{1}{2}.m.v_2^2$

$=\ \dfrac{1}{2}\times 1500\times (31.29)^2$

= 734425.84 J

Now, the ratio of final to initial kinetic energy can be given by,

$\dfrac{k_2}{k_1}=\ \dfrac{734425.84}{183606.46}$

$=>\ k_2\ =\ 4k_1$

Hence, the kinetic energy will increase by 4 times.

7 0

2 years ago