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hammer [34]
3 years ago
13

See the attachment and please can you explain.

Mathematics
1 answer:
-Dominant- [34]3 years ago
8 0
The correct answer is I because a 3:2 ratio equals a 6:4 ratio. You can simplify 6/4 to get 3/2.
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Cylinder and a cone have the same diameter: 8 inches. The height of the cylinder is 5 inches. The height of the cone is 15 inche
ss7ja [257]

Answer:

V_{cylinder}=251.2\ in^3,

V_{cone}=251.2\ in^3,

V_{cylinder}=V_{cone}.

Step-by-step explanation:

The volume of the cylinder is

V_{cylinder}=\pi r^2 h,

where r is the radius of a base circle and h is the cylinder's height.

If cylinder has diameter of 8 inches, then its radius is 4 inches. The height of the cylinder is 5 inches. Thus, the volume of the cylinder is

V_{cylinder}=3.14\cdot 4^2\cdot 5=251.2\ in^3.

The volume of the cone is

V_{cone}=\dfrac{1}{3}\pi r^2 h,

where r is the radius of a base circle and h is the cone's height.

If cone has diameter of 8 inches, then its radius is 4 inches. The height of the cone is 15 inches. Thus, the volume of the cone is

V_{cylinder}=\dfrac{1}{3}\cdot 3.14\cdot 4^2\cdot 15=251.2\ in^3.

As you can see the cylinder and the cone have the same volume.

4 0
4 years ago
Find the slope of a line parallel to the line through the given points p(-2,4) q(6,-2)
olchik [2.2K]

Answer:

(-2-4)/(6+2)= -6/8= -3/4

8 0
3 years ago
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3. A mysterious metal medallion has a mass of 3,088 grams. Water is poured into a graduated glass container with a 10-by-10 cm s
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Step-by-step explanation:

Volume of displaced water = (10cm)(10cm)(1.6cm)

= 160 cm^3

density = mass/vol of displaced water

= 3088 grams/160 cm^3

= 19.3 g/cm^3

P.S. This is most likely a pure gold medallion.

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What expressions are equivalent to -56z + 28
makvit [3.9K]

Answer:

3b+b and 2(2b)

Step-by-step explanation:


4 0
4 years ago
I need help pleaseeeeee​
MA_775_DIABLO [31]

Answer:

D

Step-by-step explanation:

5 0
3 years ago
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