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3 years ago

Find the area of a square if its sides measure 2 2/3m

Mathematics

1 answer:

olga55 [171]3 years ago

6 0

Answer:

$7\dfrac{1}{9}\ m^2$

Step-by-step explanation:

If the length of the square side is a units, then the area of the square is

$A=a^2\ un^2.$

In your case, the side length is

$a=2\dfrac{2}{3}\ m,$

then the area is

$A=2\dfrac{2}{3}\cdot 2\dfrac{2}{3}\\ \\ \\A=\dfrac{2\cdot 3+2}{3}\cdot \dfrac{2\cdot 3+2}{3}\\ \\ \\A=\dfrac{8}{3}\cdot \dfrac{8}{3}\\ \\ \\A=\dfrac{64}{9}\\ \\ \\A=7\dfrac{1}{9}\ m^2$

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The position of an object moving along an x axis is given by x = 3.24 t - 4.20 t2 + 1.07 t3, where x is in meters and t in secon

Pavel [41]

Answer and explanation:

Given : The position of an object moving along an x axis is given by $x=3.24t-4.20t^2+1.07t^3$ where x is in meters and t in seconds.

To find : The position of the object at the following values of t :

a) At t= 1 s

$x(t)=3.24t-4.20t^2+1.07t^3$

$x(1)=3.24(1)-4.20(1)^2+1.07(1)^3$

$x(1)=3.24-4.20+1.07$

$x(1)=0.11$

b) At t= 2 s

$x(t)=3.24t-4.20t^2+1.07t^3$

$x(2)=3.24(2)-4.20(2)^2+1.07(2)^3$

$x(2)=6.48-16.8+8.56$

$x(2)=-1.76$

c) At t= 3 s

$x(t)=3.24t-4.20t^2+1.07t^3$

$x(3)=3.24(3)-4.20(3)^2+1.07(3)^3$

$x(3)=9.72-37.8+28.89$

$x(3)=0.81$

d) At t= 4 s

$x(t)=3.24t-4.20t^2+1.07t^3$

$x(4)=3.24(4)-4.20(4)^2+1.07(4)^3$

$x(4)=12.96-67.2+68.48$

$x(4)=14.24$

(e) What is the object's displacement between t = 0 and t = 4 s?

At t=0, x(0)=0

At t=4, x(4)=14.24

The displacement is given by,

$\triangle x=x(4)-x(0)$

$\triangle x=14.24-0$

$\triangle x=14.24$

(f) What is its average velocity from t = 2 s to t = 4 s?

At t=2, x(2)=-1.76

At t=4, x(4)=14.24

The average velocity is given by,

$\triangle x=x(4)-x(2)$

$\triangle x=14.24-(-1.76)$

$\triangle x=14.24+1.76$

$\triangle x=16$

4 0

3 years ago

Anyone have a answer for this?

LiRa [457]

Answer:

36.1 meters

Step-by-step explanation:

Since this is a rectangle, the parallel sides are equal to each other, meaning we technically already know all the side lengths.

I'll choose to look at the bottom triangle in this case

30 is already there, and the other leg should be 20. Knowing this, we can plug these into the pythagorean theorem.

20 is A, 30 is B, and the missing side is C

$a^{2} + b^{2} = c^{2}\\20^{2} + 30^{2} = c^{2} \\400 + 900 = 1300 \\\sqrt{1300} = 36.06\\$

C, the missing side to the nearest tenth is 36.1 meters

7 0

2 years ago

A toy car shown is modeled after a real car. If the real car is 4.79 meters long, how wide is it? Select the width to the neares

ipn [44]

I think the answer I d
but I am not good at math

5 0

3 years ago

Alfred wants to waste less than 175 gallons of water this week. Every day that he waters the lawn, he wastes 59 gallons of water

victus00 [196]

L & C represent the number of days Alfred should water the lawn and wash his car respectively.
Each time he waters, there is 59 gallons used, and each time he washes car, 28 gallons used.

59L + 28C = 175 <the aim he set for himself>
59 gallons × L will then be the total amount of water he uses for watering lawn in a week.
28 gallons × C will then be the total amount of water he uses to wash his car every week.

The expression / answer : 59L + 28C = 175

Hope this helps! :)

8 0

3 years ago

Read 2 more answers

What expression must the center cell of the table below contain so that the sums of each row, each column, and each diagonal are

sergey [27]

Oh, I adore magic squares!

We need all rows to be equivalent, so try adding up the bottom (complete) row to get 7x-4x+3x=10x-4x=6x.

To solve the middle number, we have -2x+X+6x=6x, so X=2x.
To solve the top number, we have X+8x-3x=6x, so X=6x-8x+3x=x

Now check first column,
x-2x+7x=6x ok
Second column
8x+2x-4x=6x ok
Top-right to bottom-right diagonal: x+2x+3x=6x, ok
Bottom-left to top right diagonal: 7x+2x-3x=6x

So everything is ok!

5 0

3 years ago