Answer:
I think its D
Step-by-step explanation:
Because its asking for 4 less then twice the number 6 so it would be 10 and 16 btw im so sorry if im wrong
Answer:
D
Step-by-step explanation:
BD is a mid- line segment and is one half the length of AE, that is
BD = 0.5 × 21 = 10.5 → d
<h3>Answer: approximately 63.43 degrees</h3>
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Work Shown:
Locate the intersection points
f(x) = g(x)
x^2 + 2x + 1 = 1
x^2 + 2x = 1-1
x^2 + 2x = 0
x(x+2) = 0
x = 0 or x+2 = 0
x = 0 or x = -2
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Compute the derivative
f(x) = x^2 + 2x + 1
f ' (x) = 2x + 2
Then plug in each solution x value we found earlier
f ' (0) = 2(0) + 2 = 2
The slope of the tangent line at the intersection point (0,1) is m = 2
The tangent line is y = 2x+1
The angle between the lines y = 1 and y = 2x+1 is arctan(2) = 63.43 degrees approximately
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Plug x = -2 into the derivative function
f ' (x) = 2x+2
f ' (-2) = 2(-2)+2
f ' (-2) = -2
The slope of the tangent line at (-2,1) is m = -2
The tangent line here is y = -2x-3
The angle between the lines y = 1 and y = -2x-3 is also 63.43 through similar reasoning as before.
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See the diagram below.
Answer:
k = 3
Step-by-step explanation:
Expand the left side and compare the coefficients of like terms on both sides.
(2x - 1)(kx + 1) ← expand using FOIL
= 2kx² + 2x - kx - 1
Compare the coefficients of the x² term on both sides
2k = 6 ( divide both sides by 2 )
k = 3