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Ipatiy [6.2K]
2 years ago
9

Factor completely x2 − 36. (x 6)(x − 6) (x 6)(x 6) (x − 6)(x − 6) Prime.

Mathematics
1 answer:
NikAS [45]2 years ago
5 0

Thus reduced form of the given expression, using identity a^{2} -b^{2} = (a+b) (a-b) is (x+6) (x-6).

Given expression is

x^{2} -36

x^{2} -6^2

<h3>What is a reduced form of the expression a^{2} -b^{2} ?</h3>

it is (a+b) (a-b)

In the same way, we can reduce x^{2} -6^2 .

x^{2} -36 = (x+6) (x-6)

Thus reduced form of the given expression is

(x+6) (x-6)

To get more about factors refer to:

brainly.com/question/25829061

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50 POINTS! QUICKLY Are the pairs of variables x and y the solutions to the equation x^2–2y=7?
Fittoniya [83]

Hi there!

\large\boxed{(5,8) \text{ and } (1.2, -2.78)}}

We are given the equation:

x² - 2y = 7

To verify if each ordered pair is apart of the function, we can plug in their respective x and y values:

1. (5)² - 2(8) = 7

25 - 16 = 9 ≠ 7. This is NOT correct.

2. (-1)² - 2(-3) = 7

1 + 6 = 7. This is correct.

3. (-4)² - 2(-11.5) = 7

16 + 23 = 39 ≠ 7. This is NOT correct.

4. (1.2)² - 2(-2.78) = 7

1.44 +5.56 = 7. This is correct.

Thus, only 1 and 4 are the correct answers.

5 0
2 years ago
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What is the solution of 3x=67 ?
natta225 [31]

Answer:

22.3 repeating

Step-by-step explanation:

3x divided by 3x equals 1x or just x but to divide this you also have to divide the other side of the equals sign by 3 as well therefore the answer is 22.3 repeating

You might find it easy by putting it in fractions such as 3x/3x = 67/3 so x =22.3 repeating

8 0
3 years ago
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What's the solution and answer? And explain please
Advocard [28]
The solution is subtract4.7x on both sides. Then you get -2.2x=7.7. Divide 7.7 by -2.2 and you get x= -3.5
7 0
3 years ago
Which term is the rate at which work is done​
zubka84 [21]

Answer:

<h3>The answer is power.</h3>

Hope this helps you

8 0
3 years ago
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Which numbers in set ={,,,,,,,,,}eh equals left brace 1 comma 2 comma 3 comma 4 comma 5 comma 6 comma 7 comma 8 comma 9 comma 10
viva [34]

Answer:

D={3,9}

The numbers are 3 and 9

Step-by-step explanation:

The set A

={,,,,,,,,,}

Let B be the sub set of A containing odd numbers

B={1,3,5,7,9}

Let C be the sub set of A containing multiply of 3

C= {3,6,9}

Now let D be the be the sub set of A containing both odd numbers and multiples of 3

D={3,9}

5 0
3 years ago
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