Pls help I’ll brainlest ASAP

Mathematics

1 answer:

pochemuha3 years ago

5 0

Answer:

Step-by-step explanation:

112-4x = 144

-4x = 32

x = -8 incorrect answers

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I need 7-12 please!!!

sergiy2304 [10]

Answer:

number 7 is y= $\frac{-ax+c}{b}$

Step-by-step explanation:

6 0

4 years ago

Solve this equation <br>4-2x-12-2x+1

alina1380 [7]

This is not an equation because it lacks an equal sign....so the only thing we can do here is combine like terms.
4 - 2x - 12 - 2x + 1 =
-4x - 7

5 0

3 years ago

Read 2 more answers

This is really confusing me:<br> Simplify so that your answers contain only positive exponents.

xxTIMURxx [149]

Answer:

see below

Step-by-step explanation:

For simplifying expressions of this sort, there are four rules of exponents that come into play;

$a^ba^c=a^{b+c}\\\\(ab)^c=a^cb^c\\\\(a^b)^c=a^{bc}\\\\\dfrac{1}{a^b}=a^{-b}\ \quad\text{which means}\quad a^b=\dfrac{1}{a^{-b}}$

I find it convenient to eliminate the fractions by adding the exponents, then rewrite any negative exponents as denominator factors.

$23. \quad\dfrac{1}{x^{-2}}=x^2\\\\24. \quad\dfrac{mn}{m^2n^3}=m^{1-2}n^{1-3}=m^{-1}n^{-2}=\dfrac{1}{mn^2}\\\\25. \quad\dfrac{k^{-2}}{k^{-3}}=k^{-2-(-3)}=k\\\\26. \quad\left(\dfrac{m^2}{n^3}\right)^3=\dfrac{m^{2\cdot 3}}{n^{3\cdot 3}}=\dfrac{m^6}{n^9}\\\\27. \quad\dfrac{x^2y^3z^4}{x^{-3}y^{-4}z^{-5}}=x^{2-(-3)}y^{3-(-4)}z^{4-(-5)}=x^5y^7z^9$