It is important to do the
calculations very carefully. Otherwise there is nothing complicated about this
problem.
Let us assume the unknown number = x
Then
40x/100 = 55
40x = 55 * 100
40x = 5500
x = 5500/40
= 550/4
= 137.5
So
55 is 40% of 137.50. I hope the procedure is clear to you and in future
you can solve such problems on your own without requiring any help from
outside.This is the simplest way of solving such
problems.
meters cube or m³
Volume uses '³' or cube units on 3d models.
Area uses '²' or square units on 2d models.
Given:Price of one taco = x; price of 2 tacos = 2xPrice of salad = $2.50Sales tax = 8% of the combined price of two tacos and a salad, namely .08(2x + 2.50)Tip = constant fee = $3.00Total bill = $13.80 Therefore the equation becomes
2x + 2.50 + .08(2x + 2.50) + 3 = 13.80 Solutions: 2x + 2.50 + .16x + .20 + 3 = 13.80 (using the distributive property to multiply 2x and 2.5 by .08).2.16x + 2.70 + 3 = 13.80 (combining like terms)2.16x + 5.70 = 13.80 (combining like terms)2.16x + 5.70 = 13.80 - 5.70 (subtraction property of equality)2.16x = 8.10x = 8.10/2.16 = 3.75 (division property of equality)
The cost of a single taco is $3.75
Mike age is 3 less then twice the age of his brother nuke.
M = Mike's age now
N = Nuke's age now
M = 2N - 3
Ten years ago, four times nuke's age was one more mike's age.
M-10 = Mike's age 10 years ago
N-10 = Muke's age 10 years ago
4(N - 10) = 1 + M -10
what are their present ages
find M and N
substitute M = 2N - 3 into 4(N - 10) = 1 + M -10:
4(N - 10) = 1 + [2N - 3] - 10
4N - 40 = 2N - 12
2N = 28
N = 14
M = 2(14) - 3 = 28 - 3 = 25
Mike is 25 and Nuke is 14.
check:
4(14 - 10) = 4(4) = 16 = 26 -10 = 1 + 25 - 10
Answer:
Average distance traveled in 15 minutes = 7.5 miles
Step-by-step explanation:
Given function:
where 
represents average distance traveled in miles and 
represents time in minutes traveled.
To find the average distance traveled in 
minutes.
Solution:
In order to find the distance traveled in 15 minutes, we will input in the given function.
miles
Average distance traveled in 15 minutes = 7.5 miles
