Add 2 to both sdies
now if we can facor, then if
xy=0 then x and/or y=0
note:xy=x times y and x(y) =x times y
x^2+3x+2=0
what 2 number multiply to get 2 and add to get 3
the numbers are 2 and 1
(x+2)(x+1)=0
set them to zero
x+2=0
subtract 2
x=-2
x+1=0
subtract 1
x=-1
x could be -1 or -2
x=-2, or -1
Answer:
Yes
Step-by-step explanation:
I don't know the question but 2/3 is a real number.
Answer:
The answer is
<h2>20 + 56i</h2>
Step-by-step explanation:
(2 -10i) (-5 + 3i)
Using FOIL multiply each term in the first bracket by the terms in the second <u>bracket</u>
That's
2(-5) + 2(3i) - 10i(-5) - 10i(3i)
<u>Multiply the numbers and simplify</u>
We have
- 10 + 6i + 50i - 30i²
From the rules of imaginary numbers
<h3>i² = - 1</h3>
So we have
- 10 + 56i - 30(- 1)
- 10 + 56i + 30
Simplify
30 - 10 + 56i
We have the final answer as
<h3>20 + 56i</h3>
Hope this helps you
Angles 5 and 6 are not congruent because they are on the same line, so the answer is I
