A1 = 6 a5 = -6
a1 + d(n-1) = -6
6 +4d = -6
4d = -12
d = -3
a3 = a2 + d = -6 -3 = -9
Step-by-step explanation:
First,
(A intersect B) = {1,2,4,5} intersect {1,3,5,7}
= {1,5}
Now,
A'n B = (A) - (A intersect B)
= {1,2,4,5} - {1,5}
= {2,4}
41/10
4.1 = 4 1/10 = 41/10
Answer:

This will give 5 Students each in 12 different equally sized groups

This also shows that students can grouped in equal groups of 12 in 5 places
Step-by-step explanation:
From the question we are told that
60 children in equal sized groups
Generally interpreting
can be mathematically represented as
a)


This will give 5 Students each in 12 different equally sized groups
b)


This also shows that students can grouped in equal groups of 12 in 5 places