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3 years ago

Help me please much appreciated❤️

Mathematics

1 answer:

GuDViN [60]3 years ago

3 0

Answer:

X = -16

Step-by-step explanation:

2/3x plus 1 equals 1/6x minus 7

2 divided by 3 equals 0.666666666667

0.666666666667 plus 1 equals 1.666666666667

1.666666666667 as a simplified fraction: 1 35/55x

1 33 /55 – 7 = – 27 /5 = –5 2 /5

-5 2/5 x 3 = -16

(This is just how I do it but you probably did it differently)

<3 Enjoy,

Dea

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Urgent!! Will mark brainliest!!

horsena [70]

Answer:

1) x is negative and y is positive ⇒ last answer

2) cotФ = -12/35 ⇒ second answer

3) The right identity is cot²Ф - csc²Ф = -1 ⇒ last answer

Step-by-step explanation:

* For any point (x , y) lies on the terminal side of the angle Ф

in standard position

* x = cosФ and y = sinФ

- If Ф in the first quadrant, then x , y are positive

∴ All trigonometry functions are positive

- If Ф in the second quadrant, then x is negative , y is positive

∴ sinФ only is positive

- If Ф in the third quadrant, then x is negative , y is negative

∴ tanФ only is positive

- If Ф in the fourth quadrant, then x is positive , y is negative

∴ cosФ only is positive

* Lets solve the problems

∵ Ф = 3π/4 ⇒ (135°)

∴ It lies on the second quadrant

∴ x is negative and y is positive

* Lets revise the reciprocal of sinФ, cosФ and tanФ

- cscФ = 1/sinФ

- secФ = 1/cosФ

- cotФ = 1/tanФ

∵ secФ = -37/12

∴ cosФ = -12/37

∵ π/2 < Ф < π

∴ Ф lies on the second quadrant

∴ cotФ is negative values

∵ tan²Ф = sec²Ф - 1

∵ secФ = -37/12

∴ tan²Ф = (-37/12)² - 1 = 1225/144 ⇒ take√ for both sides

∴ tanФ = ± 35/12

∵ cotФ = ± 12/35

∵ cotФ is negative value

∴ cotФ = -12/35

* In the standard position of the angle Ф the terminal

of it lies on the unit circle O

- By using Pythagorean theorem

∵ x² + y² = 1

∵ x = cosФ and y = sinФ

∴ cos²Ф + sin²Ф = 1 ⇒ (1)

∴ cos²Ф = 1 - sin²Ф

∴ sin²Ф = 1 - cos²Ф

* Divide (1) by cos²Ф

∴ cos²Ф/cos²Ф + sin²Ф/cos²Ф = 1/cos²Ф

* Remember sin²Ф/cos²Ф = tan²Ф and 1/cos²Ф = sec²Ф

∴ 1 + tan²Ф = sec²Ф ⇒ (2) ⇒ subtract 1 from both sides

∴ tan²Ф = sec²Ф - 1 ⇒ subtract sec²Ф from both sides

∴ tan²Ф - sec²Ф = -1

* Divide (1) by sin²Ф

∴ cos²Ф/sin²Ф + sin²Ф/si²Ф = 1/sin²Ф

* Remember cos²Ф/sin²Ф = cot²Ф and 1/sin²Ф = csc²Ф

∴ cot²Ф + 1 = csc²Ф ⇒ (3) ⇒ subtract 1 from both sides

∴ cot²Ф = csc²Ф - 1 ⇒ subtract csc²Ф from both sides

∴ cot²Ф - csc²Ф = -1

* The right identity is cot²Ф - csc²Ф = -1

3 0

4 years ago

During the mayoral election,two debates were held between the candidates. The first debate lasted 1 2/3 hours.The second one was

butalik [34]

Answer:

2nd debate was 3 hours long.

Step-by-step explanation:

We have been given that during the mayoral election,two debates were held between the candidates. The first debate lasted 1 2/3 hours. The second one was 1 4/5 times as long as the first one.

Let us find the estimate of time spent on 2nd debate.

1 2/3 hours would be approximately 2 hours. 1 4/5 times would be equal to 2 times.

$2*2=4$

Therefore, the estimated time is less 4 hours.

To find the time spent on 2nd debate, we will multiply 1 2/3 by 1 4/5.

First of all, we will convert mixed fractions into improper fractions as:

$1\frac{2}{3}=\frac{5}{3}$

$1\frac{4}{5}=\frac{9}{5}$

Now, we will multiply both fractions as:

$\frac{5}{3}\times \frac{9}{5}$

$\frac{1}{3}\times \frac{9}{1}$

$\frac{9}{3}\Rightarrow 3$

Therefore, the 2nd debate was 3 hours long.

5 0

3 years ago

Pls help I really need the answer right now

Step2247 [10]

Use photo-math or Gauth-math application can help u this

5 0

3 years ago

Solve this : <br> 1. <img src="https://tex.z-dn.net/?f=6" id="TexFormula1" title="6" alt="6" align="absmiddle" class="latex-form

leonid [27]

6/2 (2+1)

6/ 2 x (3)

6/6 = 1

5 0

4 years ago

I don’t understand this one

Masja [62]

Answer:

see below

Step-by-step explanation:

Put -1 where x is in each expression and evaluate it.

You will find that the expression is zero when the numerator is zero. And you will find the numerator is zero when it has a factor that is equivalent to ...

(x +1)

Substituting x=-1 into this factor makes it be ...

(-1 +1) = 0

Evaluating the first expression, we have ...

$\dfrac{4(x+1)}{(4x+5)}=\dfrac{4(-1+1)}{4(-1)+5}=\dfrac{4\cdot 0}{1}=0$

This first expression is one you want to "check."

You can see that the reason the expression is zero is that x+1 has a sum of zero. You can look for that same sum in the other expressions. (The tricky one is the one with the factor (x -(-1)). You know, of course, that -(-1) = +1.)

5 0

4 years ago

Help me please much appreciated❤️​

Help me please much appreciated❤️