Answer:
C (x = 2)
Step-by-step explanation:
Since x is a non-negative number, A and B are eliminated.
This leaves C and D.
C: x = 2,
2 + 3 < 2^2
5 < 4 is false.
So C would be a counterexample.
Hope this helps!
<span>Combine the logarithms first: log5(4x+3)-log5(x-1). Since it's subtract, divide the two.
log5((4x+3)/(x-1))=2
Make both sides the exponent of five. 5^log5 cancels out.
5^(log5(4x+3/x-1))=5^2
4x+3/x-1=25
Multiply both sides by (x-1) to get rid of it under 4x+3.
(x-1)4x+3/x-1=25(x-1)
4x+3=25x-25
Now subtract 4x from both sides AND add 25 to both sides. This way you'll have all the x's by itself.
28=21x
Divide both sides by 21.
28/21=x
x=1.33333333333...
</span>
use soh cah toa!
Step-by-step explanation:
soh= sin opposite/hypotenuse
sin (65°) 5/x
* x *x
x* (sin 65°)= 5
x (0.906308) =5
÷0.906308 = ÷0.906308
x≈ 5.51689
x≈ 5.5
Answer:
Explanations:
Note that for a sequence to be arithmetic, there must be a common difference, d.
Considering each of the sequences provided:
For -1, 3, -9, 27, -81.........
3 - (-1) = 4
-9 - 3 = -12
27 - (-9) = 36
Since the differences between consecutive terms are not common, this is not an arithmetic sequence.
For 1, -2, -5, -8, -11....
-2-1 = -3
-5 -(-2) = -3
-8 - (-5) = -3
-11 - (-8) = -3
Since there is a common difference, d = -3, the sequence is an arithmetic sequence
For 26, 39, 52, 65, 78.....
39 - 26 = 13
52 - 39 = 13
65 - 52 = 13
78 - 65 = 13
Since there is a common difference of
