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Natalija [7]
3 years ago
10

Una casa de dos plantas esta construida en un terreno rectangular de 66m² , tal como lo muestra los siguientes pasos si x es el

frente de la casa y x+5 el largo. De la ecuacion cuadratica que define el area del terreno es x² + 5x-66=0 ¿Cuanto mide el frente de la casa?
Mathematics
1 answer:
Elena L [17]3 years ago
3 0

Answer:

El frente de la casa es 6 metros.

Step-by-step explanation:

El area de la casa está dada por el área de un rectángulo:

A = f*l = x (x+5) = 66

En donde f es el frente = x , l es el largo = x+5 y A es el área = 66m²

Si la ecuación cuadrática que define el área del terreno viene dado por:

x^{2} + 5x - 66 = 0          

Resolviendo la ecuación cuadrática para x tenemos:

x₁ = -11 y x₂ = 6                                

Tomando el valor positivo, podemos decir que el frente de la casa es 6 metros.

Espero que te sea de utilidad!                              

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