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cluponka [151]
3 years ago
11

Help Me Pls Thanks <3

Mathematics
1 answer:
dybincka [34]3 years ago
8 0
If there are 150 total instruments in said Orchestra, we'll need to divide that number in half.
75, simple enough. Now we know that half of 150 is 75.
Start by writing your problem like this: 150= 75w+37.5b
That equation is all I can think of, because 37.5 is half of 75, which means that's roughly the number you're looking for. Sorry if this doesn't help much<span />
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Lana71 [14]
Sum=add. difference=subtract (I'm just answering so you don't waste points)
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Which of the following is the solution to lx-13 k 18 ?
natali 33 [55]
I think d is the answer
7 0
3 years ago
The phone lines to an airline reservation system are occupied 45% of the time. Assume that the events that the lines are occupie
dimaraw [331]

Answer:

0.1569 = 15.69%

Step-by-step explanation:

If eight calls were placed, and we need to know the probability of exactly two calls were occupied, we need to calculate a combination of 8 choose 2 (all the combinations of 2 occupied calls in the 8 total calls), and multiply by the probability of each case in the 8 calls (2 cases occupied and 6 cases not occupied):

P(8,2) = C(8,2) * p(occupied)^2 * p(not_occupied)^6

P(8,2) = (8*7/2) * (0.45)^2 * (0.55)^6

P(8,2) = 28 * 0.2025 * 0.02768 = 0.1569 = 15.69%

7 0
3 years ago
A theater group made appearances into cities the hotel charge before tax and the second city was 1500 higher than the first the
Svetlanka [38]

Answer:

The hotel charge in each city before tax was <u>$5125</u> of the first city and <u>$3625</u> of the second city.

Step-by-step explanation:

Given:

A theater group made appearances into cities the hotel charge before tax and the second city was 1500 higher than the first.

The tax of the first city was 6% and the tax of the second city was 10%.

Total hotel tax paid for two cities with $670.

Now, to find the hotel charge in each city before tax.

Let the hotel charge in first city before tax be x.

And the hotel charge in second city before tax be y.

<em>So, as the hotel charge of the second city was 1500 higher than the first.</em>

<em>Thus</em>,

y=x-1500   ........(1)

<em>And as given, the tax of the first city was 6% and the tax of the second city was 10%, total hotel tax paid for two cities with $670.</em>

6% of x + 10% of y = $670.

\frac{6x}{100} +\frac{10y}{100} =670

0.06x+0.10y=670

Substituting the value of y from equation (1) we get:

0.06x+0.10(x-1500)=670

0.06x+0.10x-150=670

0.16x-150=670

<em>Adding both sides by 150 we get:</em>

0.16x=820

<em>Dividing both sides by 0.16 we get:</em>

x=5125.

<em>The hotel charge in first city before tax = $5125.</em>

Now, substituting the value of x in equation (1) we get:

y=x-1500

y=5125-1500

y=3625.

<em>The hotel charge in second city before tax = $3625.</em>

Therefore, the hotel charge in each city before tax was $5125 of the first city and $3625 of the second city.

5 0
3 years ago
A guitar factory has a cost of production C(x)=75x+50000. If the company needs to break even after 150 units sold, at what price
s2008m [1.1K]
Step by step explanation:

75x + 50000 = 150x

50000 = 75x

x = 50000/75 = 666.67



answer:

666.7 || rounded to the nearest greatest cent
4 0
2 years ago
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