___ A warm front brings warmer weather with light precipitation <br><br> A.true<br> B.false

For his craft project, James bought 1010 10 10 pieces of ribbon that were each 2.1 feet2.1\text{ feet} 2.1 feet 2, point, 1, sta

BlackZzzverrR [31]

Answer:

<h2>Total yards of ribbon bought is 6.993yards of ribbon</h2>

Step-by-step explanation:

Total pieces of ribbon James bought for his craft project = 10pieces. If each pieces of ribbon were 2.1feet long, the total number of feet for 10ribbons is expressed as;

$= 10 * 2.1\\= 21feets$

Converting 21 feets to yards;

1 feet = 0.333yard

21feets = x

x = $21feet * 0.333\\= 6.993yards$

Total yards of ribbon bought is 6.993yards of ribbon

3 0

3 years ago

Mr. Wilson invested money in two accounts. His total investment was $20,000. If one account pays 5% in interest and the other pa

blagie [28]

a = amount invested at 5%

b = amount invested at 2%

now, we know the total invested by Mr Wilson was 20000, so whatever "a" and "b" might be, we know that a + b = 20000.

$a + b = 20000\implies b = 20000-a \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{5\% of a}}{\left( \cfrac{5}{100} \right)a}\implies 0.05a~\hfill \stackrel{\textit{2\% of b}}{\left( \cfrac{2}{100} \right)a}\implies \begin{array}{llll} 0.02b\\\\ \stackrel{substituting}{0.02(20000-a)} \end{array}$

now, we know the total of earned interest is 550 bucks, so then

$0.05a~~ + ~~0.02(20000-a)~~ = ~~550\implies 0.05a+400-0.02a=550 \\\\\\ 0.03a+400=550\implies 0.03a=150\implies a=\cfrac{150}{0.03}\implies a=5000 \\\\\\ ~\hspace{24em}\stackrel{20000~~ - ~~5000}{b=15000}$