___ A warm front brings warmer weather with light precipitation A.true B.false

This pencil cup is made out of plastic. It is 5 cm long 5cm wide and 10cm

Korolek [52]

The sup is 20 cm in total in square it is route 20 which is 10x2 so if its 1.50 dhs per sqm it will be 3 x 10 which is 30 dhs
So 30 x 4 is 120 please mark as brainliest

4 0

2 years ago

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The simplest form of square root of eighty can be written as a times square root of b, where a = and b = .

lyudmila [28]

The correct answer is:

A=4

B=5

hopes this helps you and future people!

8 0

2 years ago

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Which of the following is an equation of the line that passes through the point (−2, 3) and is perpendicular to the graph of the

Ludmilka [50]

The equation of the line is $y=-\frac{1}{3}+\frac{7}{3}$

Explanation:

The given equation is $y=3 x-2$

Slope:

Since, the equation of the line is perpendicular to the equation $y=3 x-2$ , then, the slope is given by

$m=-\frac{1}{3}$

Hence, the slope is $m=-\frac{1}{3}$

Equation of the line:

The equation of the line can be determined using the formula,

$y-y_1=m(x-x_1)$

Substituting the point (-2,3) and the slope $m=-\frac{1}{3}$ , in the above formula, we get,

$y-3=-\frac{1}{3}(x+2)$

Simplifying, we get,

$y-3=-\frac{1}{3}x-\frac{2}{3}$

$y=-\frac{1}{3}x-\frac{2}{3}+3$

$y=-\frac{1}{3}+\frac{7}{3}$

Therefore, the equation of the line is $y=-\frac{1}{3}+\frac{7}{3}$

8 0

3 years ago

Determine whether or not the vector field is conservative. if it is conservative, find a function f such that f = ∇f. (if the ve

Akimi4 [234]

A three-dimensional vector field is conservative if it is also irrotational, i.e. its curl is $\mathbf 0$ . We have

$\nabla\times\mathbf f(x,y,z)=-2e^{-x}\,\mathbf k$

so this vector field is not conservative.

- - -

Another way of determining the same result: We want to find a scalar function $f(x,y,z)$ such that its gradient is equal to the given vector field, $\mathbf f(x,y,z)$ :

$\nabla f(x,y,z)=\mathbf f(x,y,z)$

For this to happen, we need to satisfy

$\begin{cases}f_x=ye^{-x}\\f_y=e^{-x}\\f_z=2z\end{cases}$

From the first equation, integrating with respect to $x$ yields

$f_x=ye^{-x}\implies f(x,y,z)=-ye^{-x}+g(y,z)$

Note that $g$ *must* be a function of $y,z$ only.

Now differentiate with respect to $y$ and we have

$f_y=-e^{-x}+g_y=e^{-x}\implies g_y=2e^{-x}\implies g(y,z)=2ye^{-x}+\cdots$

but this contradicts the assumption that $g(y,z)$ is independent of $x$ . So, the scalar potential function does not exist, and therefore the vector field is not conservative.

8 0

2 years ago

if the least value the variable k can be is 12,which of the following inequalities best shows all the possible values of k

Damm [24]

Answer:
k ≥ 12

Explanation:
We are given that the least possible value for k is 12.
This means that k can either be 12 or more.
Translating this into an inequality, we will find that the inequality is as follows:
k ≥ 12

Hope this helps :)

6 0

2 years ago