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satela [25.4K]
3 years ago
11

HELPPP WITH MATH HOMEWORK

Mathematics
2 answers:
Andre45 [30]3 years ago
6 0
B that’s it cause I’m rapping birds gonna be flapping
irga5000 [103]3 years ago
4 0

Answer:

B

Step-by-step explanation:

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What is the slope of a line perpendicular to the line whose equation is 3x-3y=543x−3y=54. Fully simplify your answer.
yaroslaw [1]
Your answer is 2x/y.
7 0
3 years ago
Which function has a vertex on the y-axis? f(x) = (x – 2)2 f(x) = x(x + 2) f(x) = (x – 2)(x + 2) f(x) = (x + 1)(x – 2)
strojnjashka [21]

we know that

If the vertex is on the y-axis, then the x-coordinate of the vertex is equal to zero

we are going to verify the vertex of each one of the functions to determine the solution

Remember that

The equation in vertex form of a vertical parabola is equal to

y=a(x-h)^{2} +k

where

(h,k) is the vertex

if a>0 -------> the parabola open upward (vertex is a minimum)

if a -------> the parabola open downward (vertex is a maximun)

<u>case A)</u> f(x)=(x-2)^{2}

This is a vertical parabola open upward

the vertex is the point (2,0)

therefore

The function f(x)=(x-2)^{2}  does not have a vertex on the y-axis

<u>case B)</u> f(x)=x(x+2)

f(x)=x(x+2)=x^{2}+2x

convert to vertex form

Complete the square. Remember to balance the equation by adding the same constants to each side.

f(x)+1=x^{2}+2x+1

Rewrite as perfect squares

f(x)+1=(x+1)^{2}

f(x)=(x+1)^{2}-1

the vertex is the point (-1,-1)

therefore

The function f(x)=x(x+2) does not have a vertex on the y-axis

<u>case C)</u> f(x)=(x-2)(x+2)

f(x)=(x-2)(x+2)=x^{2}-2^{2}

f(x)=x^{2}-4

the vertex is the point (0,-4)

The x-coordinate of the vertex is equal to zero

therefore

The function f(x)=(x-2)(x+2) has a vertex on the y-axis

<u>case D)</u> f(x)=(x+1)(x-2)

f(x)=(x+1)(x-2)\\ \\f(x)= x^{2}-2x+x-2 \\ \\f(x)= x^{2} -x-2

convert to vertex form

Group terms that contain the same variable, and move the constant to the opposite side of the equation

f(x)+2= x^{2} -x

Complete the square. Remember to balance the equation by adding the same constants to each side.

f(x)+2+0.25= x^{2} -x+0.25

f(x)+2.25= x^{2} -x+0.25

Rewrite as perfect squares

f(x)+2.25= (x-0.50)^{2}

f(x)=(x-0.50)^{2}-2.25

the vertex is the point (0.5,-2.25)

therefore

The function f(x)=(x+1)(x-2) does not have a vertex on the y-axis

<u>the answer is</u>

f(x)=(x-2)(x+2)

6 0
3 years ago
Read 2 more answers
Literally the last question pls get it right
Anna11 [10]
-1 or option c is correct. Use the given functions to set up and simplify f(−2).
5 0
3 years ago
Read 2 more answers
Write the given trinomial if possible as a square of a binomial or as an expression opposite to a square of a binomial:
Ksenya-84 [330]

\frac{4}{9}b^2 + 0.4bc + 0.09c^2 = \frac{4}{9}b^2 + \frac{4}{10}bc  + \frac{9}{100}c^2 = (\frac{2}{3}b + \frac{3}{10}c)^2

7 0
3 years ago
I = $97.30<br> P = $1,200<br> R=4.5%<br> T=
frosja888 [35]

Answer:

T = 1yrs and 8month

Step-by-step explanation:

S.I = $97.3O

S.I = PTR/100

$<u>97.30</u> = <u>$1200 × 4.5 × T</u>

1 100

Cross multiply

$5400T = $9730

divide both sides by$5400

T = 1.8yrs

8 0
3 years ago
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