We are trying to find the number that when added to 19, gives us less than 42. We can set up this simple inequality:
19 + x < 42
Now, subtract 19 from both sides:
x < 23
Our number can be anything less than 23.
Answer:
y = 2
Step-by-step explanation:
Given
![\sqrt[3]{3y+2}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B3y%2B2%7D)
+ 4 = 6 ( subtract 4 from both sides )
= 2 ( cube both sides )
3y + 2 = 2³ = 8 ( subtract 2 from both sides )
3y = 6 ( divide both sides by 3 )
y = 2
-3.073 that is the correct answer
Answer:
the first answer y=-8/5x+19.4
Step-by-step explanation:
Please tell me if the answer is right and if it is right click on thanks i appreciate it
Answer:
-17 =s
Step-by-step explanation:
-8s +4 = -7s +21
Add 8s to each side
-8s+8s +4 = -7s+8s +21
4 = s+21
Subtract 21 from each side
4-21 = s+21-21
-17 =s
