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Eddi Din [679]
3 years ago
13

Find the area of a regular pentagon with an apothem of 11 units. *

Mathematics
1 answer:
docker41 [41]3 years ago
3 0

Answer:

<h2>440 square units</h2>

Step-by-step explanation:

We can find half of a side of the pentagon with the expression

tan(36\°)=\frac{s_{half} }{11}

Because, as a regular polygon, all its sectors have the same central angle, and the apothem divides equally each sector in two equal parts.

s_{half} \approx 8

Therefore, half of a side is 8 units long, which means each side measures 16 units.

Now, the area of a penthagon is defined by

A=\frac{p \times a}{2}

Where p is the perimeter and a is the apothem. Where the perimeter is the sum of all sides, which is 80 units.

A= \frac{80 \times 11}{2} =440 \ u^{2}

Therefore, the right answer is the second choice.

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Find all solutions of the given system of equations (If the system is infinite many solution, express your answer in terms of x)
lisov135 [29]

Answer:

(a) The system of the equations \left \{ {2x-3y\:=3} \atop {4x-6y\:=3}} \right. has no solution.

(b) The system of the equations \left \{ {4x-6y\:=10} \atop {16x-24y\:=40}} \right. has many solutions y=\frac{2x}{3}-\frac{5}{3}

Step-by-step explanation:

(a) To find the solutions of the following system of equations \left \{ {2x-3y\:=3} \atop {4x-6y\:=3}} \right. you must:

Multiply 2x-3y=3 by 2:

\begin{bmatrix}4x-6y=6\\ 4x-6y=3\end{bmatrix}

Subtract the equations

4x-6y=3\\-\\4x-6y=6\\------\\0=-3

0 = -3 is false, therefore the system of the equations has no solution.

(b) To find the solutions of the system \left \{ {4x-6y\:=10} \atop {16x-24y\:=40}} \right. you must:

Isolate x for 4x-6y=10

x=\frac{5+3y}{2}

Substitute x=\frac{5+3y}{2} into the second equation

16\cdot \frac{5+3y}{2}-24y=40\\8\left(3y+5\right)-24y=40\\24y+40-24y=40\\40=40

The system has many solutions.

Isolate y for 4x-6y=10

y=\frac{2x}{3}-\frac{5}{3}

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45-28.99 is 16.01, so it's 16.01%.

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