<span>This isn't very difficult to figure out, you just need to look at these numbers in pairs. So, 16 minus 4 is 12. Then the next pair of numbers, 36 minus 9 is 27. And to complete the pattern, you just have to look at the final pair: 44 minus 11 is 33. So the number that would complete the pattern is 33.Hope this helps. Let me know if you need additional help!</span>
Simple :)
Area of shaded part = are of 1/4 circle - area of both triangles.
Are of circle = pie r^2 so 100x3.14 = 314 cm2.
Area of triangle AOB= area of triangleDOE = bh/2= 5x10/2= 25 each
However, the traingles share a common area which is quad DOB(I)
Lets take traingle AOE, whose are is bh/2=10x10/2=50cm2.
50-area of triangle A(I)E= 50-(
Answer with Step-by-step explanation:
Let A is non-singular

We have to prove that
is unique.
Suppose B and C are inverse of A such that
and AC=I
By using property 




Hence, the inverse of A is unique.
To find:
An irrational number that is greater than 10.
Solution:
Irritation number: It cannot be expression in the form of
, where,
are integers.
For example:
.
We know that square of 10 is 100. So, square root of any prime number is an example of an irrational number that is greater than 10.
First prime number after 100 is 101.
Required irrational number 
Therefore,
is an irrational number that is greater than 10.
Answer:
#carry on learning
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Find a point-slope form for the line that satisfies the stated conditions. Slope , passing through (-5,4)
I really need this question answered
By:
I don't see a value for the slope. We need that to set the equation, otherwise I can write an unlimited number of equations that pass through (-5,4).
I'll assume a slope so that you can see how the procedure would work. I like 6, so we'll assume a slope of 6.
The equation for a straight line has the form y = mx + b, where m is the slope and y is the y-intercept, the value of y when x = 0. We want a line that has slope 6, so:
y = 6x + b
We need to find b, so substitute the point (-5,4) that we know is on the line:
4 = 6*(-5) + b and solve for b
4 = -30 + b
b = 34
The line is y = 6x + 34