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Bad White [126]
3 years ago
8

Please help due today

Mathematics
1 answer:
umka21 [38]3 years ago
3 0

Answer:

y=2 x=3 i think

Step-by-step explanation:

2y+3=y+5

y=5-3

y=2

4x-3=4y+1

4x-3=4×2+1

4x-3=9

4x=9+3

4x=12

x=12/4

×=3

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How do i work out: <br> (y+3) (y-3)<br> ------- = --------- + 2<br> 4 5
Dima020 [189]
Y=13

(when you have fractions like the one in this problem, you get rid of them by multiplying both sides by the denominator.)
4 0
3 years ago
The distribution of the weights ofloaves of bread from a certain bakery follow approximately a normaldistribution. Based on a ve
slega [8]

Answer:

D)

Step-by-step explanation:

ASSUMING NORMAL DISTRIBUTION, LESS THAN 10% AT LOWER END

OF 15.34 MEANS     [DENOTING MEAN BY M AND Standard Deviation. BY S]

M±AS=20%....................M-AS=15.34

FOR 20% LEVEL .......A=1.281........FROM TABLES

M-1.281×S=15.34............................1

SIMILARLY

M±BS=40%...................M+BS=16.31

FOR 40% LEVEL .............B=0.841...................FROM TABLES

M+0.841×S=16.31.............................2

EQN.2 - EQN.1

2.122×S=0.97

S=0.457=0.46

M=15.926= 15.93

HENCE, D IS THE ANSWER

that is D. μ = 15.93, σ =.46

8 0
3 years ago
What is the square route of 5?
denis-greek [22]

Square root are the same 2 numbers multiplied.

Ex: 8*8=64 (Square root is 8)

9*9=81 (Square root is 9)

2.2360679775*2.2360679775=5

Answer=2.2360679775


6 0
3 years ago
Math help questions <br>​
Evgen [1.6K]

After 1 year, the initial investment increases by 7%, i.e. multiplied by 1.07. So after 1 year the investment has a value of $800 × 1.07 = $856.

After another year, that amount increases again by 7% to $856 × 1.07 = $915.92.

And so on. After t years, the investment would have a value of \$800 \times 1.07^t.

We want the find the number of years n such that

\$856 \times 1.07^n = \$1400

Solve for n :

856 \times 1.07 ^n = 1400

1.07^n = \dfrac74

\log_{1.07}\left(1.07^n\right) = \log_{1.07}\left(\dfrac74\right)

n \log_{1.07}(1.07) = \log_{1.07} \left(\dfrac74\right)

n = \log_{1.07} \left(\dfrac74\right) = \dfrac{\ln\left(\frac74\right)}{\ln(1.04)} \approx \boxed{8.3}

4 0
2 years ago
Read 2 more answers
!!!!!?!??!<br> Pls help me plsss
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Answer:

A is only ur answer

Hope it helps you.

8 0
2 years ago
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