Answer:
-3/2 ±1/2 sqrt(5) = x
Step-by-step explanation:
f(x) = 2x^2 + 6x + 2
Set the function equal to 0
0 = 2x^2 + 6x + 2
Factor out 2
0 = 2(x^2 + 3x + 1)
Divide by 2
0 = (x^2 + 3x + 1)
Subtract 1 from each side
-1 = x^2 +3x
Complete the square by dividing the x coefficient by 2 and then squaring
(3/2)^2 = 9/4
-1 +9/4 = x^2 +3x+9/4
-4/4+9/4 = (x+3/2) ^2
5/4 = (x+3/2) ^2
Taking the square root of each side
± sqrt(5/4) = sqrt( (x+3/2) ^2)
±1/2 sqrt(5) = (x+3/2)
Subtract 3/2 from each side
-3/2 ±1/2 sqrt(5) = x
Answer:
the value of x is 3x-3 i solve
Answer: 2/8.
Step-by-step explanation:
When we have this type of problem, the usual way to solve them is trying with known types of sequences.
I will start with the arithmetic sequence, where the difference between any two consecutive terms is a constant. And if we call this difference as D, we will have the recursive relation:
Aₙ = Aₙ₋₁ + D
To check if this sequence is an arithmetic sequence, we can take the first two terms and see the difference:
(5/8 - 3/4) = (5/8 - 6/8) = -1/8.
Now let's do the same, but with the second and third terms:
(1/2 - 5/8) = (4/8 - 5/8) = -1/8
The difference is the same, -1/8.
Now we can use the recursive relationship above and the last given term of the sequence to find the next one:
A₅ = A₄ + (-1/8)
A₅ = 3/8 - 1/8 = 2/8
Then the next fraction in the sequence was 2/8.
