A * b = 30
a - b = 1
a + b = 11
take ur last 2 equations, and add them
a - b = 1
a + b = 11
--------------add
2a = 12
a = 12/2
a = 6
now its just a matter of subbing
a + b = 11
6 + b = 11
b = 11 - 6
b = 5
so a = 6 and b = 5...whose product is 30, whose difference is 1, and whose sum is 11.
<span>y-6=-2 (x-7)
Start by distributing..
y - 6 = - 2x + 14
Add 6 to both sides...
y = - 2x + 20
Slope of this equation is -2</span>
D. combine like terms, 4+7 is 11 and -3 and -10 is -13
<span>lim (x → π/2) (sinx)^(tanx)
= lim (x → π/2) e^[(tanx) ln (sinx)]
= e^ [lim (x → π/2) (tanx) ln (sinx)] ... (1)
lim (x → π/2) (tanx) ln (sinx)
= lim (x → π/2) [ln(sinx) / cotx]
Using L'Hospital'stheorem,
= lim (x → π/2) [- cotx / cosec^2 x]
= 0
Plugging in ( 1 ),
required limit = e^0 = 1
=>Answer is 1.
I hope my answer has come to your help. Thank you for posting your question here in Brainly.
</span>
Answer:
Doesnt he still have 3? All he did was drop 2
Step-by-step explanation: