Answer:

Step-by-step explanation:
<u><em>The correct question is</em></u>
Suppose that ∅ Is an angle with csc(∅)=-12/5 and ∅ Is not in the third quadrant. Compute the exact value of Tan(∅).
∅ Is not in the third quadrant
If csc(∅) is negative the angle lie in the III Quadrant or in the IV Quadrant
∅ Is not in the third quadrant ----> given problem
so
That means ----> ∅ Is in the fourth quadrant
step 1
Find the value of 
we have

we know that

therefore

step 2
Find the value of 
we know that

we have

substitute




---> is positive (IV Quadrant)
step 3
Find the value of 
we know that

substitute the values

18 will go into 50 2.77777777778.
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Answer:
24
Step-by-step explanation:
6*[(32-8)/(4+2)]
| |
24 6
6* [24/6]
|
4
6*4 = 24
Answer:
x = -44/13
y = -65/13
Step-by-step explanation:
Using matrix form means using the crammers rule
The matrix form of the expression is written as;
![\left[\begin{array}{ccc}8&5\\-1&1\\\end{array}\right] \left[\begin{array}{ccc}x\\y\\\end{array}\right] = \left[\begin{array}{ccc}9\\7\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D8%265%5C%5C-1%261%5C%5C%5Cend%7Barray%7D%5Cright%5D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Dx%5C%5Cy%5C%5C%5Cend%7Barray%7D%5Cright%5D%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D9%5C%5C7%5C%5C%5Cend%7Barray%7D%5Cright%5D)
AX = B
taking the determinant of A;
|A| = 8(1) - 5(-1)
|A| = 8 + 5
|A| = 13
After replacing the first row with the column matrix;
![A_x =\left[\begin{array}{ccc}9&5\\7&-1\\\end{array}\right]](https://tex.z-dn.net/?f=A_x%20%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D9%265%5C%5C7%26-1%5C%5C%5Cend%7Barray%7D%5Cright%5D)
|Ax| = 9(-1)-5(7)
||Ax| = -9 - 35
|Ax| = -44
x = |Ax|/|A|
x = -44/13
similarly for y
![A_x =\left[\begin{array}{ccc}8&9\\-1&7\\\end{array}\right]](https://tex.z-dn.net/?f=A_x%20%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D8%269%5C%5C-1%267%5C%5C%5Cend%7Barray%7D%5Cright%5D)
|Ay| = 8(7)+9
|Ay| = 56+9
|Ay| = 65
y = |Ay|/|A|
y = -65/13