Pull an x from the first two terms
x(x^3 + y^3) + (x^3 + y^3) Now x^3 + y^3 is a common factor.
(x^3 + y^3)*(x + 1) That should be far enough. It can be factored further by factoring (x^3 + y^3) but there is no point because you can't do anything after that. But in case you want to know how x^3 + y^3 factors
(x^3 + y^3) = (x + y)(x^2 - xy + y^2)
Which means you could write original polynomial as
(x + y)(x^2 - xy + y^2)(x + 1)
Part B
You factored the x out of xy^3 so that you would have a common factor (x^3 + y^3) to pull out as a common factor for the whole polynomial.
Answer:
b ≈ 9.5, c ≈ 14.7
Step-by-step explanation:
Using the Sine rule in Δ ABC, that is
= 
, substitute values
= 
( cross- multiply )
b × sin23° = 7 × sin32° ( divide both sides by sin23° )
b = 
≈ 9.5 ( to the nearest tenth )
Also
= 
= 
( cross- multiply )
c × sin23° = 7 × sin125° ( divide both sides by sin23° )
c = 
≈ 14.7 ( to the nearest tenth )
Answer:
12.56 square units
Step-by-step explanation:
The formula for circumference is
C = 2πr
Our circumference is 12.56. Using 3.14 for π, we have
12.56 = 2(3.14)r
12.56 = 6.28r
Divide both sides by 6.28:
12.56/6.28 = 6.28r/6.28
2 = r
The area of a circle is given by the formula
A = πr²
Using 3.14 for π and our radius of 2, we have
A = 3.14(2²) = 3.14(4) = 12.56.
Answer:
ehhhh it's either 5or 1.59 I'm not sure Wich
Step-by-step explanation:
sorry good luck
