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Orlov [11]
3 years ago
13

Wasn’t sure how to write this out : - )

Mathematics
1 answer:
amid [387]3 years ago
5 0

we are given

\frac{\sqrt[3]{7}\sqrt{7}}{\sqrt[6]{7^5}}

we can write it in terms of exponents

\frac{7^{\frac{1}{3}}*7^{\frac{1}{2}}}{7^{\frac{5}{6}}}

Firstly , we will simplify numerator

\frac{7^{\frac{1}{3}+\frac{1}{2}}}{7^{\frac{5}{6}}}

now, we can add exponents

\frac{7^{\frac{5}{6}}}{7^{\frac{5}{6}}}

we can cancel it

and we get

=1............Answer

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4x + 7 = 23slove this
Juli2301 [7.4K]

Given:

4x + 7 = 23

Let's solve for x.

First Step:

Subtract 7 from both sides

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Next Step:

DIvide both sides by 4

\begin{gathered} \frac{4x}{4}=\frac{16}{4} \\  \\ x\text{ = 4} \end{gathered}

ANSWER:

x = 4

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