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Orlov [11]
3 years ago
13

Wasn’t sure how to write this out : - )

Mathematics
1 answer:
amid [387]3 years ago
5 0

we are given

\frac{\sqrt[3]{7}\sqrt{7}}{\sqrt[6]{7^5}}

we can write it in terms of exponents

\frac{7^{\frac{1}{3}}*7^{\frac{1}{2}}}{7^{\frac{5}{6}}}

Firstly , we will simplify numerator

\frac{7^{\frac{1}{3}+\frac{1}{2}}}{7^{\frac{5}{6}}}

now, we can add exponents

\frac{7^{\frac{5}{6}}}{7^{\frac{5}{6}}}

we can cancel it

and we get

=1............Answer

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klio [65]

<FCE = 34

<1 = <FCE = 34

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3 years ago
Please help! How on earth do I do this? In the year 2015, Anna bought a new car for $36,000. In 2017, she was told that the valu
Klio2033 [76]

Part A

Purchase Value of Anna's Car in 2015 = $36,000

Depreciated Value of Anna's Car in 2017 = $25,000

We know that the value of the car is depreciating linearly.


From the above data, we can see that the value of the car has reduced by $36,000-$25,000 = $11,000 over 2 years.

⇒ Per year the value has been depreciated by \frac{11000}{2}

⇒ Per year the value has been depreciated by $5,500

So if the value of a car in 2015 is V₀ then value of the car after t years can be determined by the below function:

V (t) = V₀ - (t*5,500), where t indicates the years passed since 2015

OR V (t) = 36,000 - (t*5,500), where t indicates the years passed since 2015

Part B

Suggested value of Anna's car for trade in option in 2018 = $15,000

In 2018, 3 years would have been passed since 2015. Using the value of t = 3 in the function determined in Part A:

V(3) = V₀ - (3*5,500)

⇒ V(3) = 36,000 - (16,500)

⇒ V(3) = $19,000

From the above calculations, we can see that the value of the car in 2018 should be $19,000, however the suggested value for trade in is indicated as $15,000 which is lower than what the value of the car should be. Hence, basis linear depreciation, the $15,000 value is not fair for the car in 2018.

3 0
2 years ago
WILL CHOOSE BRAINLIEST!!!
dsp73

Answer:

Step-by-step explanation:

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2 years ago
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Answer:

x = 7

Step-by-step explanation:

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Get the x's on one side and the integers on the other

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3 years ago
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Delicious77 [7]

Answer:

a and c

Step-by-step explanation:

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