Mu=80, sigma=39, X=85
Z=(X-mu)/sigma = 5/39=0.128=0.13
P(X<=85)= 0.5517 (from Z-table)
so, P(X>85)=1-0.5517=0.4483 approx. thats 44.8% probability.
Answer:
Area = 14.5
Step-by-step explanation:
Let's label the given coordinates A, B, C;
Thus;
A = (2, 3)
B = (-1, 0)
C = (2, -4)
From the coordinate geometry formula, the formula for area of a triangle with 3 vertices is;
Area = [Ax(By - Cy) + Bx(Cy - Ay) + Cx(Ay - By)]/2
Area = [2(0 - (-4)) + (-1)(-4 - 3) + 2(3 - (-4))]/2
Area = 29/2
Area = 14.5
0.05 rounded to the nearest whole number is 0~
A = 133; b = 31; c = 82; d = 64.
Opposite angles in an inscribed quadrilateral are supplementary; this means that d + 116 = 180. Subtracting 116 from both sides, we have d = 64.
By the same theorem, c + 98 = 180; subtracting 98 from both sides, we have c = 82.
Inscribed angles are equal to 1/2 the measure of the intercepted arc. Using this, we have
116 = 1/2(a+99)
Multiplying both sides by 2, we have
232 = a+99
Subtract 99 from both sides:
232 - 99 = a + 99 - 99
133 = a
We also have that
82 = 1/2(133+b)
Multiplying both sides by 2, we have:
164 = 133 + b
Subtract 133 from both sides:
164 - 133 = 133 + b - 133
31 = b
Two days that start with T. Seven days total. 2/7
